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1 year ago

A 5kg ball is on top of the school building at a height of 40m above the ground.

Physics

1 answer:

mojhsa [17]1 year ago

3 0

Answer:

A-Caclcuate the potential energy of the ball at that height

Explanation:

(a). Mass of the Body = 10 kg.

Height = 10 m.

Acceleration due to gravity = 9.8 m/s².

Using the Formula,Potential Energy = mgh

= 10 × 9.8 × 10 = 980 J.

(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.

∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.

∴ Kinetic Energy = 980 J.

(c). Kinetic Energy = 980 J.

Mass of the ball = 10 kg.

∵ K.E. = 1/2 × mv²

∴ 980 = 1/2 × 10 × v²

∴ v² = 980/5

⇒ v² = 196

∴ v = 14 m/s.

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Answer:

the magnitude of the electric force on the projectile is 0.0335N

Explanation:

time of flight t = 2·V·sinθ/g

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This is the horizontal acceleration of the object.

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Therefore,the magnitude of the electric force on the projectile will be

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Thus, the magnitude of the electric force on the projectile is 0.0335N

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In a given chemical reaction, the energy of the products is greater than the energy of the reactants. Which statement is true fo

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Energy is released in the reaction

Explanation:

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This indicates that the reaction is an exothermic or exergonic reaction.

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In an exothermic change energy is released to the surroundings.
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Answer:

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