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Anton [14]
3 years ago
11

A sample of fluorine-18 in a laboratory has an initial mass of 50mg.flourine-18 has a half life of 1.8 hours Calculate the amoun

t of time it will take for the initial mass of fluorine-18 to be reduced from 59 mg to 12.5mg
Physics
1 answer:
Mekhanik [1.2K]3 years ago
7 0
It will take 3.6 hours to get reduced from 50 to 12.5 g..
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Solid to liquid
Liquid to solid

By adding or removing heat energy aka thermal energy 
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Why do temperatures on the moons surface vary ncyb more than temperatures on earth
ollegr [7]

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The moon has no atmosphere

Explanation:

The temperatures on the surface of the Moon vary much more than those on Earth because the moon has no atmosphere (third answer in the list), and therefore there are no molecules that could retain residual heat and make the change from day to night a softer transition.

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AHH please help-
umka2103 [35]

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Radiation

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I hope that help's

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What is the mass of an object that has a weight of 110N ?
fgiga [73]
  • Weight (W) = 110 N
  • Acceleration due to gravity (g) = 9.8 m/s^2
  • Let the mass of the object be m.
  • By using the formula, W = mg, we get,
  • 110 N = 9.8 m/s^2 × m
  • or, m = 110 N ÷ 9.8 m/s^2
  • or, m = 11.2 Kg

<u>Answer:</u>

<em><u>The </u></em><em><u>mass </u></em><em><u>of </u></em><em><u>the </u></em><em><u>object </u></em><em><u>is </u></em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>Kg.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

3 0
3 years ago
A 2 kg blue car is moving 6 m/s to the right and collides with a 3 kg red car that is moving 2 m/s to the left. The cars collide
snow_lady [41]

Answer:

Their velocity after the collision is 1.2 m/s, to the right.

Explanation:

Given;

mass of the blue car, m₁ = 2 kg

initial velocity of the blue car, u₁ = 6 m/s

mass of the red car, m₂ = 3 kg

initial velocity of the red car, u₂ = 2 m/s

let the blue car moving to the right be in positive direction

also, let the red car moving to the left be in negative direction

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ - m₂u₂ = v(m₁ + m₂)

where;

v is their velocity after the collision

(2 x 6) - (3 x 2) = v(2 + 3)

12 - 6 = 5v

6 = 5v

v = 6/5

v = 1.2 m/s, to the right

Therefore, their velocity after the collision is 1.2 m/s, to the right.

7 0
3 years ago
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