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Anton [14]
3 years ago
11

A sample of fluorine-18 in a laboratory has an initial mass of 50mg.flourine-18 has a half life of 1.8 hours Calculate the amoun

t of time it will take for the initial mass of fluorine-18 to be reduced from 59 mg to 12.5mg
Physics
1 answer:
Mekhanik [1.2K]3 years ago
7 0
It will take 3.6 hours to get reduced from 50 to 12.5 g..
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A cat is sleeping on the floor in the middle of a 2.8-m-wide room when a barking dog enters with a speed of 1.40 m/s. As the dog
marysya [2.9K]

Answer:

the cat is  0.4238 m in front of the dog as it leaps through the window

Explanation:

Given that;

acceleration a = 0.85 m/s²

speed v = 1.40 m/s

the cat is at rest, so initial velocity u = 0  

we know that, since the cat is sleeping on the floor in the middle of a 2.8-m-wide room, it needs to cover (2.8 m / 2 ) distance to get to the window;

using the second equation equation of motion;

s = ut + 1/2 at²  

we substitute

2.8/2 = 0×t + 1/2 × 0.85 × t²

1.4 = 0.425t²

t = √( 1.4 / 0.425 )

t = 1.81497 sec

now, at acceleration 0.10 m/s²

the dog has to cover the distance;

s = ut + 1/2 at²  

s = ( 1.4 × 1.81497) - 1/2 × 0.10 × 1.81497²

s =  2.540958 - 0.1647

s = 2.3762 m  

The cant in front of the dog as it leaps through the window;

distance = 2.8 m - 2.3762 m

distance = 0.4238 m

Therefore, the cat is  0.4238 m in front of the dog as it leaps through the window

7 0
3 years ago
An experiment measures the growth of crystals in a liquid solution aboard the space shuttle. A collection of bottles has the liq
Fantom [35]

the control would be A. the bottle with 0% concentration, because you're not changing anything.

7 0
3 years ago
Read 2 more answers
Why do sound waves move faster through the ground than through the air?
lana [24]

Answer: The answer is option A.

Explanation:  Particles of matter are packed more loosely in the ground than in the air. This is true because it doesn't have thig like buildings and people stopping the sound waves.

6 0
3 years ago
Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and
mart [117]

Answer:

5.03 m

Explanation:

The wavelength of a wave is given by

\lambda=\frac{v}{f}

where

v is the speed of the wave

f is the frequency of the wave

For the sonar signal in this problem,

f=288 Hz

v=1.45\cdot 10^3 m/s

Substituting into the equation, we find the wavelength:

\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m

3 0
3 years ago
Due today HELP HELP HELP
Anna [14]

Vas happenin!

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