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3 years ago

NEED ANSWER ASAP ! WILL BRAINLIST !

Chemistry

1 answer:

nydimaria [60]3 years ago

6 0

It’s C hope it helps :) : new processes
Will be developed to locate the trees more efficiently

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The equation for one of the reactions in the process of turning iron ore into the metal is

Leona [35]

Answer:

2100g or 2.1kg

Explanation:

Based on the equation given,

One mole of Fe2O3 gives two moles of Fe

Molar mass for Fe2O3 is 160g/mol

Molar mass for two Fe is 112g/mol

Convert 3kg to gram

3×1000=3000grams

160g of Fe2O3-112 g of Fe

3000g of Fe2O3-xg of Fe

Xg=3000×112/160

Xg=2100g

To convert to kg

2100/1000=2.1kg

Mass of Fe is 2.1kg

7 0

3 years ago

How many grams of aluminum oxide (Al2O3) will be formed from 10.0 grams of aluminum (Al)? 4 AL + 3 02 --> 2 AL203

d1i1m1o1n [39]

Answer:

Mass = 18.9 g

Explanation:

Given data:

Mass of Al₂O₃ formed = ?

Mass of Al = 10.0 g

Solution:

Chemical equation:

4Al + 3O₂ → 2Al₂O₃

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 27 g/mol

Number of moles = 0.37 mol

Now we will compare the moles of Al and Al₂O₃.

Al : Al₂O₃

4 : 2

0.37 : 2/4×0.37 = 0.185 mol

Mass of Al₂O₃:

Mass = number of moles × molar mass

Mass = 0.185 mol × 101.9 g/mol

Mass = 18.9 g

4 0

3 years ago

What volume would 56.2 mL of gas at 820 mm of Hg occupy at 720 mm of Hg?

Andreyy89

Answer:

49.35 mL

Explanation:

Given: 56.2 mL of gas

To find: volume that 56.2 mL of gas at 820 mm of Hg would occupy at 720 mm of Hg

Solution:

At 820 mm of Hg, volume of gas is 56.2 mL

At 1 mm of Hg, volume of gas is $\frac{56.2}{820}$

At 720 mm of Hg, volume of gas is $\frac{56.2}{820}(720)=49.35\,\,mL$

3 0

3 years ago

I’ll give brainliest. Help me please

Doss [256]

I picture is unclear but
I can help if u send me it

7 0

3 years ago

3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh

TiliK225 [7]

Answer:

$n_{C_6H_{10}}=0.03molC_6H_{10}$

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

$n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}$

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

$m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}$

Even thought, the volume could be also computed by using its density:

$V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}$

Best regards.

4 0

3 years ago

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