Question

A tightrope walker walks across a 30 m long wire tied between two poles. The center of the wire is displaced vertically downward by 1.0 m when he is halfway across. If the tension in both halves of the wire at this point is 6250 N what is the mass of the tightrope walker?

Answer 1

Answer:

m = 84.66 kg

Explanation:

given,

tightrope walker across = 30 m

displacement vertically downward = 1 m

force at center = 6250 N

$tan \theta = \dfrac{1}{15}$

$\theta = tan{-1}{\dfrac{1}{15}$

$\theta = 3.81^0$

$2Tsin\theta =mg$

$m = \dfrac{2\times 6250\times sin 3.81^0}{9.8}$

m = 84.66 kg

hence, the mass of the tightrope walker m = 84.66 kg