Answer:
48.5 hp
Explanation:
= mass of the car = 1200 kg
= initial speed of the car = 25 km/hr = 6.94 m/s
= final speed of the car = 100 km/hr = 27.78 m/s
= time interval = 12 s
Power output of the engine is given as
W
we know that , 1 hp = 746 W
hp
hp
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Answer:
Ring v² = gh
solid wheel (cylinder) v² = 4/3 gh
Explanation:
Let's use conservation of energy to find the speed of the wheels at the bottom of the hill.
starting point. Point before starting movement
Em₀ = mgh
final point. At the bottom of the hill
Em_f = K = ½ m v² + ½ I w²
energy is conserved
Emo = Em_f
mgh = ½ m v² + ½ I w²
angular and linear velocity are related
v = w r
we substitute
mgh = ½ m v² + ½ I v² / r²
mgh = ½ (m + I / r²) v²
v² =
the moments of inertia are tabulated
Ring
I = mr²
v² = 2 m g h / (m + m)
v² = gh
solid wheel (cylinder)
I = ½ m r²
v² = 2m gh / (m + m / 2)
v² = 4/3 gh
We can see that due to the difference in the moment of inertia of each body it is different, the solid wheel has more speed when it reaches the lower part of the ramp
Answer:
The magnitude of field is 0.095T.
Explanation:
Please see attachment .