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koban [17]
2 years ago
9

A long wire carries a current toward the north in a magnetic field that is directed vertically downward perpendicular to the sur

face of Earth. What is the direction of the magnetic force on the wire
Physics
2 answers:
DerKrebs [107]2 years ago
4 0

The direction of the magnetic force on the wire is vertically downward.

We will locate the magnetic area this is as a result of transferring charges and the usage of a second right-hand rule.

The magnetic area is made by using a modern immediate wire that curls across the cord in a ring. You can discover it via pointing your right thumb in the path of the cutting-edge inside the wire and curling your fingers.

Right-hand thumb rule: in line with this rule, if we believe the linear cord conductor to be held in the grip of the right hand so that the thumb factors inside the path of the contemporary, then the curvature of the palms across the conductor will represent the route of magnetic discipline traces.

Learn more about the Right-hand thumb rule here: brainly.com/question/14434299

#SPJ4

xenn [34]2 years ago
3 0

The direction of the magnetic force on the wire is west.

The magnetic force acting on the moving protons acts northward in the horizontal plane. If the thumb is up (current flows vertically up), the wrapped finger will be counterclockwise.

Therefore, the direction of the magnetic field is counterclockwise. Here, the magnetic field is pointing upwards (vertical magnetic field) and the electrons are moving east. Applying Fleming's left-hand rule here, we can see that the direction of force is along the south direction.

As the change in magnetic flux increases upwards, Lenz's law indicates that the induced magnetic field of the induced current must resist and the inside of the loop must be directed downwards. Using the right-hand rule, we can see that a clockwise current is induced.

Learn more about the magnetic fields here: brainly.com/question/7802337

#SPJ4

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How do you solve <img src="https://tex.z-dn.net/?f=4x%5E%7B3%7D" id="TexFormula1" title="4x^{3}" alt="4x^{3}" align="absmiddle"
Vlad1618 [11]

Hello There!

Here's a explanation!

Let's solve your equation step-by-step.

4x^3=2x^-^1

4x^3=\frac{2}{x}

Step 1: Multiply both sides by x.

4x^4=2

\frac{4x^4}{4} =\frac{2}{4}

(Divide both sides by 4).

x^4=\frac{1}{2}

x=+(\frac{1}{2} )^(^\frac{1}{4} ^)

Take the root.

ANSWER!

x=0.840896 Or x=-0.840896

Hopefully, this helps you!!

AnimeVines

8 0
3 years ago
Q1: An object with a charge of 1.2 C is located 4.5 m away from a second object that has a charge of 0.36 C. Find the electrical
gizmo_the_mogwai [7]

Answer:

a) F= 0,19  [N]   according to problem statement

b) F = 0,19*10⁹ [N]  using the right value of K

Explanation:

The force between two electric charges is according to Coulomb´s law is:

F = K * q₁*q₂ / d²    where  q₁  and q₂ are the charges on body one and body 2 respectively, d is the distance between the two bodies and K is a constant  K = 8,988100*10⁹ N.m²/C². The problem establishes to use        K = 8,988100 N.m²/C².

NOTE: To value of is :  K = 8,988100*10⁹ N.m²/C². I am going to solve the problem using K = 8,988100 N.m²/C² if that information was an error, all we need to get the right answer is multiply the result by 10⁹

Then:

F = 8,988100 * 1,2* 0,36 / (4,5)²     [ N*m²/C² ] * [ C*C*/m²]

F = 3,882859/ 20,25  [N]

F= 0,19  [N]

The force is of repulsion since the two charges are positive and in the direction of the straight line which passes through the centers of the bodies

4 0
3 years ago
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exis [7]

v2 = ?

m1 = 10kg

m2 = 70kg

v1 = 4m/s

E1 = E2

E1 = 1/2 * m1 * v1^2 = 1/2 * 10kg * 4m/s^2 = 80J

E2 = 1/2 * m2 * v2^2 = 80 J

v2 = √(E2/(2 * m2)) = √(80J/(2 * 70kg)) = about 0.76m/s

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3 years ago
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Zina [86]

Answer:

Explanation:

the first one is D

8 0
3 years ago
If you drop a bowling ball, a tennis ball, and a feather from the top of a tall building at the same time, which one will hit th
olasank [31]

They hit at the same time. Everything falls at the same rate.

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