0 and 1 are neither prime nor composite. A prime is any number greater than 1 that has just 1 and itself as factors. Primes can only start at x > 1
When that happens (when you start with numbers greater than one) p^2 is a composite consisting of 2 primes, so any composite will obey the law that he number will have at least 3 factors making it up -- in this case p p^2 and 1.
So the answer to the question by definition is that 0 numbers can have the property of both p and p^2 to be prime.
The problem is,
→ (2√3)/√12
Let's simplify the problem,
→ (2√3)/√12
→ (2√3)/(√4 × √3)
→ (2√3)/(2 × √3)
→ (2√3)/(2√3) = 1
Hence, the answer is 1.
