Answer:
Explanation:
A chemical formula can be defined as a notation that is used to show which element and how many is contained in a chemical compound.
Also, in chemistry, the sum of charges of the anion and the cation of any ionic compound is always equal to zero.
A chemical equation is considered to be balanced when the amount of reactants on the left is equal to the amount of products on the right.
Therefore;
[2]FeBr3 + [3]Na2S → [1]Fe2S3 + [6]NaBr
In the above chemical equation, we will balance the reactants in the chemical equation with the smallest coefficients possible;
Two (2) moles of Iron (III) Bromide reacts with two (2) moles of Sodium Sulfide to form Iron (III) Sulfide and Sodium Bromide.
Answer:
Inhibition and tolerance.
Explanation:
Competitive inhibitors are characterized by being chemicals that are similar to the normal substrate. While non-competitive inhibitors are chemicals that bind to the enzyme and alter its shape. This renders the active site of the enzyme ineffective against the substrate. Tolerance makes a society that is fair and equitable.
Answer:
0.721 g/L
Explanation:
Ideal gas equation ->PV= nRT ; n= mass (m)/ molar mass (M);
densitiy= mass (m)/ volume (V)
PV= (m/M)*RT -> PVM= mRT -> PM/RT= m/V -> PM/RT=d
We need to put in SI units
105 Kpa= 1.04 atm
25°C= 298 K
d= (1.04 atm * 17 g/ mol)/(0.0821 * 298 K) = 0.721 g/L
Answer:
75 g
Step-by-step explanation:
<em>Step 1. </em>Calculate the molar mass of CaCO₃
Ca = 40.08
C = 12.01
3O = 3 × 16.00 = <u> 48.00
</u>
Total = 100.09 g/mol
<em>Step 2</em>. Calculate the mass of the pellet
Mass of CaCO₃ = 0.75 mol × (100.09 g/1 mol)
Mass of CaCO₃ = 75 g
Answer: A) 1
Explanation:
Lithium is the third element of the periodic table with atomic number of 3. The atomic number is equal to the number of electrons for a neutral atom and thus there are 3 electrons in Lithium.
The electronic configuration of Lithium (Li) is 
. Thus it can gain one electron to complete its octet and attain stability. Thus it can form one bond with other atoms.
Example: Lithium can form one bond with flourine to form LiF by losing one electron to form 
.
