Answer:
ΔF=125.22 %
Explanation:
We know that drag force on the car given as
=Drag coefficient
A=Projected area
v=Velocity
ρ=Density
All other quantity are constant so we can say that drag force and velocity can be given as
Now by putting the values
Percentage Change in the drag force
ΔF=125.22 %
Therefore force will increase by 125.22 %.
Answer:
the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Explanation:
Given that;
final velocity v = 0
initial velocity u = 15m/s
time taken t = 4 s
acceleration a = ?
from the equation of motion
v = u + at
we substitute
0 = 15 + a × 4
acceleration a = -15/4 = - 3.75 m/s²
the negative sign tells us that its a deacceleration so the sign can be ignored.
Deacceleration due to friction a = μ × g
we substitute
3.75 = μ × 9.8
μ = 3.75 / 9.8 = 0.3826 ≈ 0.38
Therefore the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Answer
given,
mass of crate attached by cable A = 160 Kg
mass of crate attached by cable B = 73 Kg
acceleration of helicopter = 1.4 m/s²
tension in the cable when the move up
F = m (a + g)
tension in cable B
F = 73 x (1.4 + 9.8)
F = 73 x 11.2
F = 817.6 N
tension in cable A
F = (160 + 73 ) x (1.4 + 9.8)
F = 233 x 11.2
F = 2609.6 N
Answer:
Approximately 8years
Explanation:
1 year is 365 days and since there are 24 × 60 minutes in a day, then there will be 24 × 60 × 365 minutes in a year, which is 525,600 minutes in one year.
Since one year makes 525609minues, then according to the question, in 4.25 x 10^6 minutes (4250000minutes), there will be:
4250000 ÷ 525600
= 8.08
Approximately there will be 8 years in 4.25 x 10^6 minutes
