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andrew-mc [135]
3 years ago
5

What is 72 tens - 12tens

Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0
Solve:-

72 tens - 12 tens
72 tens - 12 tens = 72 - 12 = 60
72 tens - 12 tens = 60 tens 
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(07.04 LC)What is the solution to the equation ax = 2?
Karo-lina-s [1.5K]

Answer:

x=12 .  

Step-by-step explanation:

See image below:)

3 0
3 years ago
Complete the description of the piecewise function graphed below. Use interval notation to indicate intervals.
Gemiola [76]

Answer:

{ -2 if x ∈ -4 < x < -3

{ -5 if x ∈ -3 ≤ x < 2

[ 5 if x ∈ 2 ≤ x < 5    

Step-by-step explanation:

From the graph, we have;

{ -2 if x ∈ -4 < x < -3

For the next inequality line at y = -5, we have;

1) The inequality line, starts with an open circle on the left at x = -3, which is equivalent to less than or equal to symbol, ≤ as -3 ≤ x because the point x =-3 is the left boundary.  The inequality line extends to the point x = 2, where we have a closed circle (on the right), which is equivalent to a x ≤ 2 with the 2 on the right hand side because, the 2 is the right boundary of the inequality

2) The inequality can be summarized as starting from x = -3 extends to x = 2

3) As stated in point 1) the point x = 3, we have -3 ≤ x and at point x = 2, we have x ≤ 3 which can be combined as  -3 ≤ x < 2, to give;

{ -5 if x ∈ -3 ≤ x < 2

For the next inequality line at y = 5, we have;

1) The inequality line, starts with an open circle on the left at x = 2, which is equivalent to less than or equal to symbol, ≤ as 2 ≤ x because the point x =2 is the left boundary.  The inequality line extends to the right to reach point x = 5, where we have a closed circle (on the right), which is equivalent to a x ≤ 5 inequality, with the 5 on the right hand side because, the 5 is the right boundary of the inequality

2) The inequality can be summarized as starting from x = 2 extends to x = 5

3) As stated in point 1) the point x = 2, we have 2 ≤ x and at point x = 5, we have x ≤ 5 which can be combined as  2 ≤ x < 5, to give;

[ 5 if x ∈ 2 ≤ x < 5.

7 0
3 years ago
Simplify expression X^2+x-2/x^3-x^2+2x-2
professor190 [17]

Answer:


=\frac {x+2}{x^2+2} is the simplest form of given expression.


Step-by-step explanation:

The given question is \frac{x^2+x-2}{x^3-x^2+2x-2}


To solve the problem we have to group or split middle term and then factorise


\frac{x^2+(2x-x)-2}{(x^3-x^2)+(2x-2)}


Taking x^2 common from first two terms of denominator and 2 from next two terms


= \frac{x^2+2x-x-2}{x^2(x-1)+2(x-1)}


Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms


= \frac{ x(x+2)-1(x+2)}{(x-1)(x^2+2)}



=\frac{(x+2)(x-1)}{(x-1)(x^2+2)}


Now cancel out x-1 from both numerator and denominator we get


=\frac {x+2}{x^2+2} is the required simplest form.



7 0
3 years ago
0.357 round to 2 decimal places
Andrej [43]
.36. Just put that in
7 0
4 years ago
Read 2 more answers
Hi, can someone please answer this question? Thanks!!!
cricket20 [7]

Answer:

sorry im not so sure abut the answer

Step-by-step explanation:

.....

8 0
4 years ago
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