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3 years ago

What is 72 tens - 12tens

Mathematics

1 answer:

olchik [2.2K]3 years ago

8 0

Solve:-

72 tens - 12 tens
72 tens - 12 tens = 72 - 12 = 60
72 tens - 12 tens = 60 tens

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A = (5) b = (3) Work out 4a + b

malfutka [58]

Step-by-step explanation:

IF A=5, B=3

4*5+3=20+3

=23

THE ANSWER IS 23

8 0

2 years ago

Multiply. Write in simplest form. Help pls!! Tell me the answer no decimals needed just a fraction and simplified!! 2 3/5 x 3 7/

Lady bird [3.3K]

Answer:

10 3/40

Step-by-step explanation: hope i helped

7 0

2 years ago

Help me pleaseeeeeeeee

MAVERICK [17]

It Would Be B x+3/x-3

4 0

3 years ago

Read 2 more answers

For every 1 litre of water used to make a medicine, 193ml of sucrose and 61ml of saline solution are used. Express the amount of

Brilliant_brown [7]

<h3>Answer is the ratio 1000:193:61</h3>

Explanation

1 liter = 1000 mL

For every 1000 mL of water, we need 193 mL of sucrose and 61 mL of saline solution.

The ratio is therefore 1000:193:61

We cannot simplify this ratio any further because the GCF of those three terms is 1.

A quick way to see this is to look at how 1000 = (2*5)^3 has prime factors 2 and 5, but 2 nor 5 are factors of 193 and 61. So only 1 is a factor of all three values 1000, 193, 61

7 0

3 years ago

Please can someone help me with this question

sasho [114]

Answer:

r = - $\frac{6a}{1-5m^2}$

Step-by-step explanation:

Rewrite the equation as $\sqrt{x} 6a+r/5r$ = m

Remove the radical on the left side of the equation by squaring both sides of the equation.

( $\sqrt{\frac{6a+r}{5r} )^{2}$ = m^2

Then, you simplify each of the equation.

Rewrite: ( $\sqrt{\frac{6a+r}{5r} )^{2}$ as $\frac{6a+r}{5r} = m^{2}$

Remove any parentheses if needed.

Solve for r.

Multiply each term by r and simplify."

Multiply both sides of the equation by 5.

6a+r= m^2r⋅(5)

Remove parentheses.

Move 5 to the left of (m ^2) r

6a+r=5m^2)r

Subtract 5m^2)r from both sides of the equation.

6a+r-5m^2)r=0

Subtract 6a from both sides of the equation.

r-5m^2)r=-6a

Factor r out of r-5m^2)r

r(1-5m^2)=-6a

Divide each term by 1-5m^2 and simplify.

r = - $\frac{6a}{1-5m^2}$

There you go, hope this helps!

4 0

3 years ago