Answer:
correct option is a. 0.2 mA toward D
Explanation:
given data
B carries = 1.5 mA
C carries current = 1.3 mA
solution
we take positive direction of current going away from the point D
and negative direction of current coming towards point D
so we use here kirchoff's current law that is
iA + iB + iC = 0 ......................1
iA + 1.5 + (-1.3) = 0
iA = - 0.2 mA
so that current in wire A is 0.2 mA towards point D
correct option is a. 0.2 mA toward D
Answer:
3.6 x 10⁻⁷ H
Explanation:
C = capacitance of the capacitor = 6.57 x 10⁻¹² F
L = inductance of the inductor = ?
f = frequency of broadcasting system = 103.9 MHz = 103.9 x 10⁶ Hz
frequency is given as
Inserting the values
L = 3.6 x 10⁻⁷ H
Answer: 9.33fm
Explanation:
Similarly as with a cut diffraction happens when part of the proliferating wave is cut off. This will occur for any object of request with a similar size as the wavelength of the diffracting wave.
Note, the object is moving at 14% of the speed of light. Be that as it may, the gamma factor is just 1% so taking care of the issue either relativistic or non relativistic conditions offers comparative responses.
Note: The size of the object has to be of the order of the wavelength of 10MeV. Therefore, size apperture that would be necessary to observe diffraction effect would be 9.33fm.
The calculations are in the attachment below:
