7.17m/s glad I could help
Answer:
7.50 cm
Explanation:
The formula
1/v + 1/u = 1/f
Is used.
where.
u is the object distance.
v is the image distance.
f is the focal length of the lens.
1/v + 1/15 = 1/5
1/v = 1/5 - 1/15
1/v = (3-1)/15
1/v = 2/15
2v = 15
V = 15/2
V = 7.5 cm
For focal length, f in lens is always taken as negative for concave and positive for convex. ... And for image distance, V in lens it is taken as positive in Convex lens since image is formed on +X side. It is taken as negative in Concave lens since image is formed in -X side of the Cartesian.
Answer:
λ
=8.57 μ m
Explanation:
Given that
Ey = 375 cos [kx − (2.20 × 10¹⁴ rad/s)t] N/C
Standard form
Ey=Eo cos[k x-ωt] N/C
By comparing the given equation with the standard wave equation
Eo = 375 N/C
ω = 2.20 × 10¹⁴ rad/s
We know that ω = 2 π f
f=3.50×10¹³ Hz
We know that the velocity given as
V = f λ
λ
=Wavelength
V=Speed = 3 x 10⁸ m/s
λ
=0.00000857 m ( 1 μ m = 10⁶ m)
λ
=8.57 μ m
The time taken by the ballast bag to reach the ground is 2.18 s
The ballast bag at rest with respect to the balloon has the upward velocity (u) of 4.6 m/s , which is the velocity of the balloon. When it is dropped from the balloon, its motion is similar to an object thrown upwards with an initial velocity <em>u </em>and it falls under the acceleration due to gravity<em> g.</em>
Taking the upward direction as positive and the downward direction as negative, the following equation of motion may be used.

The bag makes a net displacement <em>s</em> of 13.4 m downwards, hence

Its initial velocity is

The acceleration due to gravity acts downwards and hence it is negative.

Use the values in the equation of motion and write an equation for t.

Solving the equation for t and taking only the positive value for t,
t=2.18 s