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Drupady [299]
3 years ago
5

The influence of blood vessel diameter on peripheral resistance is ________.

Physics
1 answer:
NeX [460]3 years ago
6 0

Answer:

The influence of diameter of the blood vessel on peripheral resistance is significant because resistance is inversely proportional to the fourth power of the diameter.

Explanation:

The influence of diameter of the blood vessel on peripheral resistance is significant because the relation between the peripheral resistance and the diameter is given as, resistance is inversely proportional to the fourth power of the diameter. Thus, with small increase or decrease in the value of diameter, the peripheral resistance may vary by a significant amount.

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A sheet of steel 1.4 mm thick has nitrogen atmospheres on both sides at 1200°C and is permitted to achieve a steady-state diffus
marta [7]

Answer:

9.1 × 10^-4m

Explanation:

From Fick's first law of diffusion:

J = -D dc/dx

Where J ,= diffusion flux

D = diffusion coefficient and dc/dx = concerntration gradient

Since we can assume a linear concentration profile, we rewrite the equation above as:

J = - D ◇c/◇x = -D (Cs - Cx)/(0 - x)

Where Cs = surface concerntration

C = concerntration of depth

X = target variable

J = diffusion flux = 1.0×10^-7kg/m^2/s

D ,= diffusion coefficient = 7.0×10^-12m^2/s

Substituting into the equation

1.0 ×10^-7 = (-7.0×10^-11)(4.9 -3.6) / ( 0 - X)

1.0 × 10^-7 = (-9.1 ×10^-11)/(0 - X)

Cross multiply

(1.0 ×10^-7) ×(0-X) = (-9.1 ×10^-11)

X = (-9.1 × 10^-11)/(-1.0 × 10^-7)

X = 9.1 × 10^-4m

7 0
3 years ago
What is the best example of an activity that works the rectus abdominus?O Bench pressO CrunchPull ups
earnstyle [38]
The answer is Crunch.
5 0
4 years ago
A gas expands and does PV work on its surroundings equal to 319 J. At the same time, it absorbs 136 J of heat from the surroundi
LiRa [457]

Answer:

The change in energy of the gas during the process is -1.83\times 10^{2} joules.

Explanation:

We can represent this process by the First Law of Thermodynamics, in which gas does work on its surroundings and absorbs heat from there to describe its change in energy. In other words:

Q_{in} - W_{out} = \Delta E

Where:

Q_{in} - Heat absorbed by the gas, measured in joules.

W_{out} - Work done by the gas, measured in joules.

\Delta E - Change in energy, measured in joules.

If we know that Q_{in} = 1.36\times 10^{2}\,J and W_{out} = 3.19\times 10^{2}\,J, the change in energy of the gas is:

\Delta E = 1.36\times 10^{2}\,J-3.19\times 10^{2}\,J

\Delta E = -1.83\times 10^{2}\,J

The change in energy of the gas during the process is -1.83\times 10^{2} joules.

3 0
3 years ago
In which of these biomes do nutrients cycle fastest?
nordsb [41]

Answer:

the answer is tropical rainfores

7 0
3 years ago
A 1090 kg car moving +11.0 m/s
stiks02 [169]

The mass of the second car is 1434.21 kg

<u>Explanation:</u>

Using law of conservation of momentum,

          m_{1} u_{1}+m_{2} u_{2}=\left(m_{1}+m_{2}\right) v

Given:

m_{1} = 1090 kg

u_{1} = 11 m/s

u_{2} = 0

v = 4.75 m/s

We need to find m_{2}

When substituting the given values in the above equation, we get

(1090 \times 11)+\left(m_{2} \times 0\right)=\left(1090+m_{2}\right) 4.75

11990=5177.5+4.75 m_{2}

4.75 m_{2}=11990-5177.5

4.75 m_{2}=6812.5

m_{2}=\frac{6812.5}{4.75}=1434.21 \mathrm{kg}

6 0
3 years ago
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