Answer:
6.113 atm
Explanation:
Data provided in the question:
Molarity of the solution = 0.25 M
Temperature, T = 25° C = 25 + 273 = 298 K
Now,
Osmotic pressure (π) is given as:
π = MRT
where,
M is the molarity of the solution
R is the ideal gas constant = 0.082057 L atm mol⁻¹K⁻¹
on substituting the respective values, we get
π = 0.25 × 0.082057 × 298
or
π = 6.113 atm
Answer:
19.3 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 12.4 kg
Volume (V) = 642 mL.
Density (D) =.?
Next, we shall convert 12.4 kg to grams. This can be obtained as follow:
1 kg = 1000 g
Therefore,
12.4 kg = 12.4 × 1000
12.4 kg = 12400 g
Therefore, 12.4 kg is equivalent to 12400 g.
Finally, we shall determine the density of the gold as follow:
Density is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:
Density (D) = mass (m) / volume (V)
D = m/V
With the above formula, the density of gold can easily be obtained as follow:
Mass (m) = 12400 g
Volume (V) = 642 mL.
Density (D) =.?
D = m/V
D = 12400/642
D = 19.3 g/mL
Therefore, the density of hold is 19.3 g/mL
No one can do that by him or her self
Chloroplasts is the answer
Answer:
the volume is 20 just subtract
Explanation:
