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2 years ago

Which equation represents a hyperbola with a center at (0, 0), a vertex at (−48, 0), and a focus at (50, 0)?

2 answers:

8 0

<span>The center, vertex, and focus all lie on the line y = 0. Then we know that the equation of a hyperbola is a^2 + b^2 = c^2 . a^2 represents the x part of the equation and the y part will be subtracted. We know that the vertex is 48 units from the center and that the focus is 50 units from the center. Then we have that b^2 = 2500 - 2304 = 196 . Thus the equation that represents the hyperbola is x^2/2304 - y^2/196 = 1 or 49x^2 -576y^2 - 112896 = 0</span>

KiRa [710]2 years ago

8 0

Its B im sure. i just took the test

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Jim Panzee got in a taxi that charges a $10 flat fee plus $3 per mile traveled. Write an equation that shows the relationship be

nekit [7.7K]

Answer:

the total is $25 for a 5 mile ride.

the total is $40 for a 10 mile ride.

Step-by-step explanation:

x*3+y= total

5*3=$15

$15+$10=$25

10*3=$30

$30+$10=$40

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3 years ago

What is the quotient of 15,048 and 76

vitfil [10]

Answer:

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3 years ago

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3 years ago

On a factory floor, 65 out of every 140 toy robots is defective. What percent of the toy robots are defective? Round your answer

tester [92]

Answer:

65/140

as a percentage is 46.43

hundredth rounding

46.4

Step-by-step explanation:

8 0

2 years ago

The hypotenuse of a right triangle measures 58 cm and one of its legs measures 42 cm. What is the length of the missing leg? 10

Nutka1998 [239]

If the hypotenuse is 58cm, and one of the others legs is 42cm the answer would be 40cm

Explanation:

Here you have to use the formula

${a}^{2} + {b}^{2} = {c}^{2}$
Then you have to pose the formula in terms of one of the legs, so:

${a}^{2} = {c}^{2} - {b}^{2}$
$a = \sqrt{ {c}^{2} - {b}^{2}}$
So when you change the letter for numbers you have that:

$a = \sqrt{ {58}^{2} - {42}^{2} }$

a=40

5 0

2 years ago