What is an alloy?

A car jack with a mechanical advantage of 6 needs to produce an output force of 600 N to raise a car. What input force is requir

Mkey [24]

B.) 100 N is the CORRECT answer

Please mark as brainliest! :)

6 0

3 years ago

Read 2 more answers

What type of music classes would you lime to see next year?

Alexus [3.1K]

Answer:

If I were you, I would recommend a trumpet its the easiest instrument to play butits my opinion its your decision.

Explanation:

8 0

3 years ago

Ted throws an object straight up into the air with an initial velocity of 54 ft/s from a platform that is 40 ft above the ground

elena-s [515]

Answer:

The time it will take for the object to hit the ground will be 4.

Explanation:

You have:

h(t)=−16t²+v0*t+h0

Being v0 the initial velocity (54 ft/s) and h0 the initial height (40 ft) and replacing you get:

h(t)=−16t²+54*t+40

To know how long it will take for the object to touch the ground, the height h(t) must be zero. So:

0=−16t²+54*t+40

Being a quadratic function or parabola: f (x) = a*x² + b*x + c, the roots or zeros of the quadratic function are those values of x for which the expression is 0. Graphically, the roots correspond to the points where the parabola intersects the x axis. To calculate the roots the expression is used:

$\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}$

In this case you have that:

a=-16
b= 54
c= 40

Replacing in the expression of the calculation of roots you get:

$\frac{-54+\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}$ Expresion (A)

and

$\frac{-54-\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}$ Expresion (B)

Solving the Expresion (A):

$\frac{-54+\sqrt{5476 } }{2*(-16)}= \frac{-54+74}{2*(-16)}=\frac{20}{2*(-16)}=\frac{20}{-32}= -\frac{5}{8}$

Solving the Expresion (B):

$\frac{-54-\sqrt{5476 } }{2*(-16)}= \frac{-54-74}{2*(-16)}=\frac{-128}{2*(-16)}=\frac{-128}{-32}= 4$

These results indicate the time it will take for the object to hit the ground can be -5/8 and 4. Since the time cannot be negative, then the time it will take for the object to hit the ground will be 4.

6 0

3 years ago

A gymnast with mass 46.0 kg stands on the end of a uniform balance beam as shown. The beam is 5.00 m long and has a mass of 250

worty [1.4K]

Sum up the moments of the right and the left support:
∑ M2 = 0
F1 · 3.92 m = 46 kg · 9,81 m/s² · 4.46 m + 250 kg · 9.81 m/s² · 1.96 m
F 1 · 3.92 = 2012.6 + 4806.9
F 1 = 6819.5 : 3.92
F 1 = 1739.67 N
∑ M 1 = 0
F 2 · 3.92 m + 46 kg · 9.81 m/s² · 0.54 m = 250 kg · 9.81 m/s² · 1.96 m
F 2 · 3.92 + 243.68 = 4806.9
F 2 · 3.92 = 4563.22
F 2 = 4563.22 : 3.92
F 2 = 1164 N
Answer: The forces on the beam are: F 1 = 1739.67 N and F 2 = 1164 N.

3 0

3 years ago

No nuclear reactions occur in the interior of a white dwarf. its brilliance comes from stored heat. therefore, the fate of an is

Snowcat [4.5K]

For a white dwarf star to become explosively active, the gap between the dwarf and therefore the companion should be sufficiently little that the white dwarf's force field will pull matter aloof from the surface of the companion. because of the rotation of the positional representation system, the matter flowing through the mass-transfer stream from the companion star forms a flat disk, known as associate degree accretion disk, that orbits round the white dwarf star.

3 0

2 years ago