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Agata [3.3K]
2 years ago
10

What is the molar mass of the anhydrous compound? Answer using four significant figures.

Chemistry
2 answers:
Alex73 [517]2 years ago
5 0

Answer:

120.15

Explanation:

ta edg

Tomtit [17]2 years ago
5 0

Answer:

120.15

Explanation:

edg 2021

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A 10.0 gram sample of Fe contains how many miles of Fe
Dafna1 [17]

Answer:

1.7857 moles

Explanation:

moles=mass/Mr

10/56=1.7857

moles of iron =1.7857

4 0
2 years ago
Increasing the temperature of the solvent ____________________ the solubility of a solid solute and _______________________ the
Marina86 [1]

Answer:

increase in solvent temperature will increase the solubility of solid particle but decreases the solubility of gas particle.

Explanation:

In solid particle when temperature increases its help to break apart the solid particle and increase in kinetic energy of solvent results in increase in solubility of solid particles in solvent.

but in gas solute, increase in temperature of solvent causes the increase in motion of gas molecules means increase in kinetic energy of molecules in the gas which results in breakage of inter molecular bonds and removal of the molecules from the heated solution.

4 0
2 years ago
What is the product of SO2+H2O. ​
Mariulka [41]

Answer:

H2O + SO2 → H2SO3

Explanation:

H2O + SO2 → H2SO3

6 0
2 years ago
Read 2 more answers
If He gas has an average kinetic energy of 4310 J/mol under certain conditions, what is the root mean square speed of O2 gas mol
Free_Kalibri [48]

Answer:

The root mean square speed of O2 gas molecules is

<u>519.01 m/s</u>

<u></u>

Explanation:

The root mean square velocity  :

v_{rms}=\sqrt{\frac{3RT}{M}}

K.E_{avg}=\frac{3}{2}RT

K.E =\frac{1}{2}mv_{rms}^{2}

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

K.E of He =

K.E_{avg}=\frac{3}{2}RT

T=\frac{2(K.E)}{3(R)}

K.E of He = 4310 J/mol

T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}

T=345.60K

<u>Now , Use Vrms to calculate the velocity of O2</u>

v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}

v_{rms}=\sqrt{\frac{8619.9552}{0.032}}

v_{rms}=\sqrt{26935.001}

v_{rms}=519.01m/s

6 0
3 years ago
What is the mass, in grams, of a cube of copper that has a volume of 62.2 cm3?
SashulF [63]

) Copper density= 8.96 g/cm³ Copper volume= 51.3c.m.3  Copper density = M/V8.96= M/51. M= 459.68g.m.

7 0
3 years ago
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