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yanalaym [24]
4 years ago
14

In the previous problem, Ken predicted a drop in

Mathematics
1 answer:
erma4kov [3.2K]4 years ago
3 0

Answer:

Explained below.

Step-by-step explanation:

First of all, an integer is a whole number that can be either positive, negative or zero.

Now, a drop in temperature signifies a reduction in the temperature.

This means that if for example, the current temperature is 50 °C, a drop in temperature of 10°C would mean that the current temperature would be gotten by subtracting 10 from 50.

Now,current temperature after drop would be;

T = 50 - 10

To prove that it is gotten by adding a negative integer:

This can also be written as;

T = 50 + (-10)

Because from mathematical multiplication signs, minus multiplied by plus gives minus.

Since, T = 50 + (-10), it means that a negative integer of minus 10 has been added to the initial temperature to get the new decreased temperature.

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Answer:

p_v =P(t_{17}    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

The best option for this case would be:

We would switch to α = .01 for a more powerful test.

Step-by-step explanation:

Previous concepts and data given  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=37.8 represent the sample mean  

s=5.4 represent the sample standard deviation  

n=18 represent the sample selected  

\alpha=0.05 significance level  

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is less than 40, the system of hypothesis would be:    

Null hypothesis:\mu \geq 40    

Alternative hypothesis:\mu < 40    

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

t=\frac{37.8-40}{\frac{5.4}{\sqrt{18}}}=-1.728      

P-value

First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

Since is a left tailed test the p value would be:    

p_v =P(t_{17}    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

The best option for this case would be:

We would switch to α = .01 for a more powerful test.

Since the p values is just a little higher than th significance level 0.051>0.05  but the values are two close. If we change the value of the significance by 0.01, we have that 0.051>0.01 and it's a more powerful test.

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