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vladimir1956 [14]
4 years ago
10

A body is thrown vertically upward with velocity 20m/s .How long time it remains in air? (g=10m/s2)

Physics
2 answers:
harina [27]4 years ago
6 0

Answer:

\boxed{\sf Time \ being \ in \ which \ body \ remains \ in \ air = 4 \ s}

Given:

Velocity (u) = 20 m/s

Acceleration due to gravity (g) = 10 \sf m/s^2

To Find:

Time (t) being in which body remains in air.

Explanation:

Formula:

\boxed{\bold{\sf t=\frac{2u}{g}}}

Substituting values of u & g in the equation:

\sf \implies t = \frac{2 \times 20}{10}

\sf \implies t =\frac{40}{10}

\sf \implies t =\frac{4 \times \cancel{10}}{ \cancel{10}}

\sf \implies t = 4 \ s

\therefore

Time (t) being in which body remains in air = 4 seconds

DiKsa [7]4 years ago
3 0
I don’t know, it depends if they have a parachute and can deploy it quickly enough. If they do, the drag and air resistance would gently bring them down at a much slower pace than freefalling. Not enough information to solve this.
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Explanation:

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FBD is attached with where we can see the horizontal and vertical component of force.

⇒ F_x=Fcos(\theta)          and             ⇒ F_y=Fsin (\theta)

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⇒ \sum F_x=F_n_e_t =F-f

⇒ F_n_e_t =F-f

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Magnitude of the acceleration of the crate is 0.362 m/s^2.

4 0
3 years ago
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