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ratelena [41]
3 years ago
11

A man seeking to set a world record wants to tow a 101,000-kg airplane along a runway by pulling horizontally on a cable attache

d to the airplane. The mass of the man is 84 kg, and the coefficient of static friction between his shoes and the runway is 0.76. What is the greatest acceleration the man can give the airplane? Assume that the airplane is on wheels that turn without any frictional resistance.
Physics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

6.19 x 10^{-3} m/s^{2}

Explanation:

For this exercise we need to sum the forces on the y-axis and x-axis as follows:

∑F_{y} = N - mg = m.a_{y} = 0

From the exercise, we deduce there is no motion in y-axis, so:

N = mg

Then for x-axis we have:

∑F_{x} = H - f^{s} = m.a_{x} = 0

Now, from the exercise we deduce that we are looking for the greatest static friction which means to have the maximun static friction to start moving, so at this point the acceleration is zero, so we can find horizontal force (H), which then will act in the airplane to move it. Therefore we have:

H = f^{s} = f^{sma_{x} } = u_{s}N = u_{s}mg

H = (0.76)(84Kg)(9.8m/s^{2})

H = 625.63 N

Now we apply this force to the weight of the plane to find the greatest acceleration the mann can give to start moving the plane.

a = \frac{F}{m} = \frac{H}{m}

a = \frac{6325.63N}{101000Kg}

a = 6.19 x 10^{-3} m/s^{2}

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2. While standing near a bus stop, a student hears a distant horn beeping. The frequency emitted by the horn is 440 Hz. The bus
jarptica [38.1K]

Given Information:

Frequency of horn = f₀ = 440 Hz

Speed of sound = v = 330 m/s

Speed of bus = v₀ = 20 m/s

Answer:

Case 1. When the bus is crossing the student = 440 Hz

Case 2. When the bus is approaching the student = 414.9 Hz

Case 3. When the bus is moving away from the student = 468.4 Hz

Explanation:

There are 3 cases in this scenario:

Case 1. When the bus is crossing the student

Case 2. When the bus is approaching the student

Case 3. When the bus is moving away from the student

Let us explore each case:

Case 1. When the bus is crossing the student:

Student will hear the same frequency emitted by the horn that is 440 Hz.

f = 440 Hz

Case 2. When the bus is approaching the student

f = f₀ ( v / v+v₀ )

f = 440 ( 330/ 330+20 )

f = 440 ( 330/ 350 )

f = 440 ( 0.943 )

f = 414.9 Hz

Case 3. When the bus is moving away from the student

f = f₀ ( v / v+v₀ )

f = 440 ( 330/ 330-20 )

f = 440 ( 330/ 310 )

f = 440 ( 1.0645 )

f = 468.4 Hz

6 0
3 years ago
a surface recieving sound is moved from it original position to a position three times farther away from the source of the sound
Delicious77 [7]
Sound intensity = 1/(r^2)

That is Sound intensity is indirectly proportional to  the distance. Therefore, sound becomes 9 times less intense.
7 0
2 years ago
Give THREE examples of objects that have potential energy
Tasya [4]

A ball kept on 3rd floor of a building.

A pendulum bob kept at 3m height

A stone thrown vertically upward.

A pressed spring.

A squashed spunge ball.

4 0
3 years ago
Two resistors have resistances R(smaller) and R(larger), where R(smaller) < R(larger). When the resistors are connected in se
ASHA 777 [7]

Answer:

R = 9.85 ohm , r = 0.85 ohm

Explanation:

Let the two resistances by r and R.

when they are connected in series:

V = 12 V

i = 1.12 A

The equivalent resistance when they are connected in series is

Rs = r + R

So, By using Ohm's law

V = i Rs

Rs = V / i = 12 / 1.12 = 10.7 ohm

R + r = 10.7 ohm    .... (1)

When they are connected in parallel:

V = 12 V

i = 9.39 A

The equivalent resistance when they are connected in parallel

R_{p}=\frac{R+r}{rR}

So, By using Ohm's law

V = i Rp

Rp = V / i = 12 / 9.39 = 1.28 ohm

\frac{R+r}{rR}=1.28    .... (2)

by substituting the value of R + r from equation (1) in equation (2), we get

r R = 8.36 ..... (3)

R-r = \sqrt{\left ( R+r \right )^{2}-4rR}

R-r = \sqrt{\left ( 10.7 \right )^{2}-4\times 8.36}=9 ..... (4)

By solvng equation (1) and (4), we get

R = 9.85 ohm , r = 0.85 ohm

8 0
3 years ago
The star Betelgeuse is about 600 light-years away. If it explodes tonight,
Thepotemich [5.8K]

Answer:

C

Explanation:

It has to travel 600 light years before we would be able to observe the explosion.

4 0
3 years ago
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