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ratelena [41]
3 years ago
11

A man seeking to set a world record wants to tow a 101,000-kg airplane along a runway by pulling horizontally on a cable attache

d to the airplane. The mass of the man is 84 kg, and the coefficient of static friction between his shoes and the runway is 0.76. What is the greatest acceleration the man can give the airplane? Assume that the airplane is on wheels that turn without any frictional resistance.
Physics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

6.19 x 10^{-3} m/s^{2}

Explanation:

For this exercise we need to sum the forces on the y-axis and x-axis as follows:

∑F_{y} = N - mg = m.a_{y} = 0

From the exercise, we deduce there is no motion in y-axis, so:

N = mg

Then for x-axis we have:

∑F_{x} = H - f^{s} = m.a_{x} = 0

Now, from the exercise we deduce that we are looking for the greatest static friction which means to have the maximun static friction to start moving, so at this point the acceleration is zero, so we can find horizontal force (H), which then will act in the airplane to move it. Therefore we have:

H = f^{s} = f^{sma_{x} } = u_{s}N = u_{s}mg

H = (0.76)(84Kg)(9.8m/s^{2})

H = 625.63 N

Now we apply this force to the weight of the plane to find the greatest acceleration the mann can give to start moving the plane.

a = \frac{F}{m} = \frac{H}{m}

a = \frac{6325.63N}{101000Kg}

a = 6.19 x 10^{-3} m/s^{2}

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8 0
3 years ago
Which of the following activities could lead to injuries?
Ipatiy [6.2K]

Answer:

Fighting

Explanation:

Fighting with someone like punch for punch can make the person bleed which an injury to the guy who you fought with and you can be arrested if the parents file a complain at the police station

6 0
3 years ago
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If the area of an iron rod is 10 cm by 0.5 cm and length is 35 cm. Find the value of resistance, if 11x10^-8 ohm.m be the resist
malfutka [58]

Answer:

Resistance of the iron rod, R = 0.000077 ohms    

Explanation:

It is given that,

Area of iron rod, A=10\ cm\times 0.5\ cm=5\ cm^2 = 0.0005\ m^2

Length of the rod, L = 35 cm = 0.35 m

Resistivity of Iron, \rho=11\times 10^{-8}\ \Omega-m

We need to find the resistance of the iron rod. It is given by :

R=\rho\dfrac{L}{A}

R=11\times 10^{-8}\times \dfrac{0.35\ m}{0.0005\ m^2}

R=0.000077 \Omega

So, the resistance of the rod is 0.000077 ohms. Hence, this is the required solution.

6 0
3 years ago
Atmospheric conditions near a mountain range are such that a cloud at an altitude of 2.00 km contains 3.20 ✕ 10^7 kg of water va
kykrilka [37]

Answer:

time required is 6.72 years

Explanation:

Given data

mass m = 3.20 ✕ 10^7 kg

height h = 2.00 km = 2 × 10^3 m

power p = 2.96 kW  =2.96 × 10^3 J/s

to find out

time period

solution

we know work is mass × gravity force × height

and power is work / time

so we say that power =  mass  gravity force × height / time

now put all value and find time period

power =  mass × gravity force × height / time

2.96 × 10^3 =  3.20 ✕ 10^7  × 9.81× 2 × 10^3  / time

time =  62.784 × 10^10 / 2.96 × 10^3

time = 21.21081081 × 10^7 sec

time = 58.91891892 × 10^3 hours

time = 6.72 years

so time required is 6.72 years

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3 years ago
GETS BRAINILIST!!!!Which of the following will increase the gravitational force exerted by one object on another? Increasing the
jeka94

Answer:

C. Decreasing the distance between the objects.

Explanation:

Gravitational force depends on mass and distance. The farther the objects are apart, the less gravitational force/pull they have.

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