What is the average access time for a hard disk spinning at 360 revolutions per second with a seek time of 10 milliseconds?

Physics

1 answer:

antoniya [11.8K]3 years ago

3 0

As the hard disk makes 360 revolutions per second, so one full rotation requires 1/360 sec = 0.002778 sec = 2.778 ms.

On average, however, we expect to require half a rotation. Therefore, we need 1.389 ms. The second part of the movement depends on the seek time which is 10 ms. Therefore, the total time is 1.389+10=11.389 ms on average.

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For the pendulum in this problem, we have

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and

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