Ir=Initial Intensity/Area of spread=Io4πr2
Ir∝1r2
It is seen from this expression that intensity is inversely proportional to the square of the distance. As we move away from the light source the intensity decreases at the rate of square of the distance from the source.
Brightness being the perception of intensity. more the intensity more bright the object is perceived and vice versa.
Answer:
The oscillation frequency of the spring is 1.66 Hz.
Explanation:
Let m is the mass of the object that is suspended vertically from a support. The potential energy stored in the spring is given by :
k is the spring constant
x is the distance to the lowest point form the initial position.
When the object reaches the highest point, the stored potential energy stored in the spring gets converted to the potential energy.
Equating these two energies,
.............(1)
The expression for the oscillation frequency is given by :
(from equation (1))
f = 1.66 Hz
So, the oscillation frequency of the spring is 1.66 Hz. Hence, this is the required solution.
Answer:
The value is 
Explanation:
From the question we are told that
The initial speed is 
at a distance of 
The final speed is 
at a distance of 
Generally from the kinematic equation we have that
=> 
=> 
=>
The negative sign shows that it is decelerating
Answer:
hope this helps have a great day!
Explanation:
Answer:
there are 3.018 kcal= 3018 cal per gram of candy
Explanation:
If the assume that the calorimeter is perfectly insulated, then all the heat released by the combustion is absorbed by the calorimeter.
Also knowing that Q= C * ΔT , where C= heat capacity of the calorimeter , ΔT= temperature change , Q = heat released by the combustion of the candy
replacing values
Q = C * ΔT = 33.90 kJ/°C * 2.46°C = 83.394 kJ
since Q is the heat released when burned all the mass m of the candy, the number of calories per gram of candy will be
q = Q/m =83.394 kJ / 6.60 g = 12.635 kJ/g
q = 12.635 kJ/g * 1 kcal / 4.186 kJ = 3.018 kcal per gram of candy
