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Nikitich [7]
2 years ago
5

FOR EXTRA POINTS What is 50+44*69-22

Mathematics
2 answers:
ankoles [38]2 years ago
8 0

Answer:

The answer is 3064 :D

Step-by-step explanation:

Paha777 [63]2 years ago
3 0
The to the question answer is 3064
You might be interested in
there are 18 boys and 24 girls who want to participate in the trivia challenge. if each team must have the same number of boys a
Fittoniya [83]

The greatest number of teams that can enter will be 6.

The number of girls will be =2

The number of boys will be = 4

Teams within an enterprise are groups of personnel all working below a shared designation or for a shared goal. groups may be shaped in a selection of structures relying on the desires of the commercial enterprise.

working together saves time and presents each person with more strength to focus on getting the task done. with the aid of getting your employees to work as a team, you may improve the productivity levels of all and sundry present. you may actualize innovative thoughts with greater efficiency, making the importance of teamwork clean.

The reason for a group is to determine how a completely unique set of people can use their abilities to perform an intention at a particular time. A clear team reason can assist motivate individuals into motion. a few advantages of understanding the purpose of a crew include growing recognition and inclusion.

The number of girls = is 18.

Number of boys = 24

Based on the information given, in order to find the greatest number of teams that can enter, we have to find the highest common factors for both boys and girls. This will be:

Factors of 18 = 1, 2, 3, 6, 9, 18.

Factors of 24 = 1, 2, 3, 4, 6, 8, 12, 16, 24.

Highest common factor = 6

Therefore, the greatest number will be 6.

The number of girls will be =2

The number of boys will be = 4

Learn more about teams here brainly.com/question/4311312

#SPJ4

3 0
1 year ago
Please help ASAP !!15 points!!
DIA [1.3K]

Answer:

i got 48x as my answer if its wrong sorry

3 0
3 years ago
Evaluate g(x)=6x when x=-3,0, and 4 .
hram777 [196]

Answer:

-3 = -18

0 = 0

4 = 24

Step-by-step explanation:

-3... so 6(-3) equals -18 because a positive times a negative equals a negative

0... so 6 (0) equals 0 because anything multiplied by 0 equals 0

4... so 6 (4) equals 24

() means multiplied by so if it’s y(x) then that means y is multiplied by x :)

3 0
3 years ago
Let n1equals50​, Upper X 1equals30​, n2equals50​, and Upper X 2equals10. Complete parts​ (a) and​ (b) below. a. At the 0.05 leve
Viefleur [7K]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

Step-by-step explanation:

1) Data given and notation  

X_{1}=30 represent the number of people with a characteristic in 1

X_{2}=10 represent the number of people with a characteristic in 2

n_{1}=50 sample of 1 selected  

n_{2}=50 sample of 2 selected  

p_{1}=\frac{30}{50}=0.6 represent the proportion of people with a characteristic in 1

p_{2}=\frac{10}{50}=0.2 represent the proportion of people with a characteristic in 2

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion 1 is different from proportion 2 , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{30+10}{50+50}=0.4  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.  

3 0
3 years ago
5. A survey of student pizza preferences showed that 43 students preferred cheese, 56 preferred sausage, 39 preferred pepperoni,
cestrela7 [59]

Answer:

P (Cheese) = 0.199, P (Sausage) = 0.259, P (Pepperoni) = 0.181,

P (Supreme) = 0.130, P (Another Kind) = 0.144

and P (Does not like any kind) = 0.088

Step-by-step explanation:

Given:

Number of students who prefer cheese = 43

Number of students who prefer sausage = 56

Number of students who prefer pepperoni = 39

Number of students who prefer supreme = 28

Number of students who prefer another kind = 31

Number of students who did not like any kind = 19

∴ The total number of students surveyed = 43+56+39+28+31+19=216       The number of students who prefer pizza = 43+56+39+28+31=197

The probability that a students likes pizza is,

P(Student\ likes\ pizza)=\frac{No.\ of\ students\ who\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                     =\frac{197}{216} \\=0.912

The probability that a students does not likes pizza is,

P(Student\ does\ not\ likes\ pizza)=\frac{No.\ of\ students\ who\ does\ not\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                                   =\frac{19}{216} \\=0.088

The probability distribution of students who prefer different kinds of pizza is:

  • The probability that a student likes cheese:

       P(A\ Student\ prefers\ cheese)=\frac{No.\ of\ students\ who\ prefer\ cheese}{Total\ no.\ of\ students\ surveyed}

                                                       =\frac{43}{216}\\=0.199

  • The probability that a student likes sausage:

        P(A\ Student\ prefers\ sausage)=\frac{No.\ of\ students\ who\ prefer\ sausage}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{56}{216}\\=0.259

  • The probability that a student likes pepperoni:

       P(A\ Student\ prefers\ pepperoni)=\frac{No.\ of\ students\ who\ prefer\ pepperoni}{Total\ no.\ of\ students\ surveyed}  

                                                             =\frac{39}{216}\\=0.181

  • The probability that a student likes supreme:

       P(A\ Student\ prefers\ supreme)=\frac{No.\ of\ students\ who\ prefer\ supreme}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{28}{216}\\=0.130

  • The probability that a student likes another kind:

        P(A\ Student\ prefers\ another\ kind)=\frac{No.\ of\ students\ who\ prefer\ another\ kind}{Total\ no.\ of\ students\ surveyed}

                                                                   =\frac{31}{216}\\=0.144

Thus, the probability distribution table is displayed below:

6 0
3 years ago
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