Answer:
It's B, anything about a circle is Stationary
Give me some answer choices and i will be happy to help
X=1/2 at^2
3.1=1/2 a *0.64
a=9.68
v=at
v=0.8*9.6875=7.75
Till the time car is just adjacent to the bicycle we can say
distance moved by cycle = distance moved by car
Time taken by car to accelerate from rest


Time taken by cycle to accelerate

now the distance moved by cycle in time "t"

distance moved by car in same time

now make them equal



so cycle will move ahead of car for t = 5.68 s
Answer:
In most cases, the sources of information for both levels are same as follows:
Verbal or personal contacts : This information is transferred through verbal method. ...
Different media: Media is one of the best sources of information in these days.
Explanation: