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3 years ago

TRUE OR FALSE : Boyle’s law states that, as the pressure of a gas increases, the volume decreases.

1 answer:

8 0

At first glance, this statement seems to be true. But after about a
microsecond of further consideration, one realizes that the statement
would actually set Boyle spinning in his grave, and is false.

Boyle's law states that there is a firm relationship among the pressure,
temperature, and volume of an ideal gas, and that you can't say anything
about how any two of these quantities depend on each other, unless you
also say what's happening to the third one at the same time.

As the pressure of an ideal gas increases, the volume will decrease in
direct proportion to the volume, IF THE TEMPERATURE OF THE GAS
REMAINS CONSTANT.

If you wanted to, you could increase the pressure AND the volume of an
ideal gas both at the same time. You would just need to warm it enough
while you squeeze it.

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Density=2g/mL and volume=20mL what is mass

leva [86]

Answer:

40g

Explanation:

Mass = density x volume

= 2 x 20

= 40g

8 0

3 years ago

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Suppose someone pours 0.250 kg of 20.0ºC water (about a cup) into a 0.500-kg aluminum pan with a temperature of 150ºC. Assume th

Troyanec [42]

Answer : The temperature when the water and pan reach thermal equilibrium short time later is, $59.10^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of aluminium = $0.90J/g^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_1$ = mass of aluminum = 0.500 kg = 500 g

$m_2$ = mass of water = 0.250 kg = 250 g

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of aluminum = $150^oC$

$T_2$ = initial temperature of water = $20^oC$

Now put all the given values in the above formula, we get:

$500g\times 0.90J/g^oC\times (T_f-150)^oC=-250g\times 4.184J/g^oC\times (T_f-20)^oC$

$T_f=59.10^oC$

Therefore, the temperature when the water and pan reach thermal equilibrium short time later is, $59.10^oC$

8 0

3 years ago

A bus is traveling with a uniform acceleration of 2.75 meters/second2. If the initial velocity of the bus is 16.5 meters/second,

Kaylis [27]

<span>The velocity will be 41.25 m/s2 after 9 seconds. To find velocity after a specific time period, multiply the acceleration (2.75) times the number of seconds (9) to receive 24.75 m/s, then add that to the initial velocity of 16.5 m/s. 24.75 + 16.5 = 41.25 m/s2.</span>

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3 years ago

What happens when the object is placed at F? Explain your answer.

sp2606 [1]

Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.

6 0

3 years ago

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A rock is projected from the edge of the top of a building with an initial velocity of 21.6 m/s at an angle of 37◦ above the hor

dusya [7]

<h2>Horizontal component of the rock’s velocity when it strikes the ground is 17.25 m/s</h2>

Explanation:

In horizontal direction there is no acceleration or deceleration for a rock projected at an initial angle of 37° off the ground.

So the horizontal component of velocity always remains the same.

Horizontal component of velocity is the cosine component of velocity.

Initial velocity, u = 21.6 m/s

Angle, θ = 37°

Horizontal component of velocity = u cosθ

Horizontal component of velocity = 21.6 cos37

Horizontal component of velocity = 17.25 m/s

Since the horizontal velocity is unaffected, we have

Horizontal component of the rock’s velocity when it strikes the ground = 17.25 m/s

5 0

3 years ago