Answer:
v = √2G
/ R
Explanation:
For this problem we use energy conservation, the energy initiated is potential and kinetic and the final energy is only potential (infinite r)
Eo = K + U = ½ m1 v² - G m1 m2 / r1
Ef = - G m1 m2 / r2
When the body is at a distance R> Re, for the furthest point (r2) let's call it Rinf
Eo = Ef
½ m1v² - G m1
/ R = - G m1
/ R
v² = 2G
(1 / R - 1 / Rinf)
If we do Rinf = infinity 1 / Rinf = 0
v = √2G
/ R
Ef = = - G m1 m2 / R
The mechanical energy is conserved
Em = -G m1
/ R
Em = - G m1
/ R
R = int ⇒ Em = 0
Answer:
a) Linear equation
Explanation:
Definition of acceleration

if a=constant and we integrate the last equation

So the relation between the time and the velocity is linear. If we plot the velocity in function of time, the plot is a line, and the acceleration is the slope of this line.
V=IR
V=15x11
V=165ohms
I don’t quite remember the unit
Ohms law
Answer with Explanation:
We are given that
Velocity,v=24 m/s west
Acceleration,a=
(N of W)
Horizontal component of acceleration=Tangential acceleration
Tangential acceleration,
Radial acceleration=Vertical acceleration=

Radial acceleration,



Time,


Acceleration a = F/m = 20/4 = 5 m/s^2
v = a x t = 5 × 5 =25 m/s