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alisha [4.7K]
3 years ago
10

TRUE OR FALSE : Boyle’s law states that, as the pressure of a gas increases, the volume decreases.

Physics
1 answer:
sveta [45]3 years ago
8 0

At first glance, this statement seems to be true.  But after about a
microsecond of further consideration, one realizes that the statement
would actually set Boyle spinning in his grave, and is false.

Boyle's law states that there is a firm relationship among the pressure,
temperature, and volume of an ideal gas, and that you can't say anything
about how any two of these quantities depend on each other, unless you
also say what's happening to the third one at the same time.

As the pressure of an ideal gas increases, the volume will decrease in
direct proportion to the volume, IF THE TEMPERATURE OF THE GAS
REMAINS CONSTANT.

If you wanted to, you could increase the pressure AND the volume of an
ideal gas both at the same time.  You would just need to warm it enough
while you squeeze it.

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Remaining Time: 1 hour, 49 minutes, 34 seconds.
ohaa [14]

Explanation:

i think C . it is twice the size of the object

4 0
3 years ago
. 30
schepotkina [342]

Answer:

Explanation:

Length if the bar is 1m=100cm

The tip of the bar serves as fulcrum

A force of 20N (upward) is applied at the tip of the other end. Then, the force is 100cm from the fulcrum

The crate lid is 2cm from the fulcrum, let the force (downward) acting on the crate be F.

Using moment

Sum of the moments of all forces about any point in the plane must be zero.

Let take moment about the fulcrum

100×20-F×2=0

2000-2F=0

2F=2000

Then, F=1000N

The force acting in the crate lid is 1000N

Option D is correct

7 0
3 years ago
One speaker generates sound waves with amplitude A.
raketka [301]

Answer:

iv) It is 9x bigger than before

Explanation:

As the amplitudes of the new speakers add directly with the original one, taking into account the phase that they have, the composed amplitude of the sound wave is as follows:

At = A + 4A -2A = 3 A

The intensity of the wave, assuming it propagates evenly in all directions, is constant at a given distance from the source, and can be expressed as follows:

I = P/A

where P= Power of the wave source, A= Area (for a point source, is equal to the surface area of a sphere of radius r, where is r is the distance to the source along a straight line)

For a sinusoidal wave, the power is proportional to the square of the amplitude, so the intensity is proportional to the square of the amplitude also.

If the amplitude changes increasing three times, the change in intensity will be proportional to the square of the change in amplitude, i.e., it will be 9 times bigger.

So, the statement iv) is the right one.

7 0
3 years ago
A thin, taut string tied at both ends and oscillating in its third harmonic has its shape described by the equation y(x, t) = (5
barxatty [35]

Answer:

A thin, taut string tied at both ends and oscillating in its third harmonic has its shape described by the equation y(x,t)=(5.60cm)sin[(0.0340rad/cm)x]sin[(50.0rad/s)t]y(x,t)=(5.60cm)sin[(0.0340rad/cm)x]sin[(50.0rad/s)t], where the origin is at the left end of the string, the x-axis is along the string, and the y-axis is perpendicular to the string. (a) Draw a sketch that shows the standing-wave pattern. (b) Find the amplitude of the two traveling waves that make up this standing wave. (c) What is the length of the string? (d) Find the wavelength, frequency, period, and speed of the traveling waves. (e) Find the maximum transverse speed of a point on the string. (f) What would be the equation y(x, t) for this string if it were vibrating in its eighth harmonic?

4 0
3 years ago
Calculate the average linear momentum of a particle described by the following wavefunctions: (a) eikx, (b) cos kx, (c) e−ax2 ,
Maksim231197 [3]

Answer:

a) p=0, b) p=0, c) p= ∞

Explanation:

In quantum mechanics the moment operator is given by

              p = - i h’  d φ / dx

             h’= h / 2π

We apply this equation to the given wave functions

a)  φ = e^{ikx}

        .d φ dx = i k e^{ikx}

We replace

        p = h’ k e^{ikx}

        i i = -1

The exponential is a sine and cosine function, so its measured value is zero, so the average moment is zero

            p = 0

b) φ = cos kx

           p = h’ k sen kx

The average sine function is zero,

          p = 0

c) φ = e^{-ax^{2} }

         d φ / dx = -a 2x  e^{-ax^{2} }

         .p = i a g ’2x  e^{-ax^{2} }

       The average moment is

         p = (p₂ + p₁) / 2

         p = i a h ’(-∞ + ∞)

         p = ∞

6 0
3 years ago
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