To do this, we're going to use the order of operations (PEMDAS):
P - Parentheses
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction
First let's do parentheses, there isn't anythig in parentheses we need to simplify, so we can skip this step.
Next let's look for exponents. I see we have a 
so let's replace that with 
:
Now let's look for multiplcation. We know that things that are right next to eachother in parentheses represent multiplcation, so let's simply this more:
And now we're left with a simple problem we know how to solve.
Answer: 
Hope this helps!
The number<span> is between integers, so it can't be an integer or a whole </span>number<span>. It's written as a ratio of two integers, so it's a </span>rational number<span> and not irrational. All</span>rational numbers<span> are real </span>numbers<span>, so this </span>number<span> is </span>rational<span> and real.</span>
Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
Now the last section, 2(-2)^3
Exponents first: (-2)^3 is -2 * -2 * -2, which is -8.
-8*2=-16.
0+4+(-16)=-12
You have the function
.
Rewrite it in the following way:
.
This <span>function entry allows you to determine that y=96 is the horizontal asymptote and x=-8/5 is the vertical asymptote.
</span>
From the added graph of the function you can conclude that <span>the maximum number of moose that the forest can sustain at one time is 96.</span>
Answer: Correct choice is A.
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