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Ivanshal [37]
3 years ago
9

1 HELP

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

The force applied to the spring is 35,780 N

Explanation:

Given;

extension of the spring, x = 200 mm = 0.2 m

energy stored in the spring, E = 3578 J

The force applied to the spring is calculated as;

E = ¹/₂Fx

where;

F is the applied force

F = 2E/x

F = ( 2 x 3578) / 0.2

F = 35,780 N

Therefore, the force applied to the spring is 35,780 N

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What is the velocity?
Blababa [14]

Answer:

B. 0.98 m/s

Explanation:

This is because we use the simple formula of dividing the distance by the time. In which case would be 13.69m (distance) divided by 13.92s (time) and we will get 0.983477011 or 0.98m/s (your answer)

I hope this made sense and hoped it helped. Good luck with your test luv :)

8 0
3 years ago
A car starting from rest accelerates at a constant 2.0 m/s2 for 10 s. It then travels with constant speed it has achieved for an
Anon25 [30]

Answer:

The total distance will be 400 m.

Explanation:

For portion AB:

Acceleration = 2m/s^2

t= 10 s

Car start from rest , u=0 m/s

We know that

S=ut+\dfrac{1}{2}at^2

S=0+\dfrac{1}{2}\times 2\times 10^2

S= 100 m.

For portion BC:

V= u + at

V=0 + 2 x 10

V= 20 m/s

In this portion car moves with constant velocity  20 m/s for 10 s.

So distance S= V x t

S=20 x 10 =200 m.

For portion CD:

The velocity at point C will be 20 m/s

In this portion the final speed of car will be zero because given that at final car come to rest.

So the acceleration will be in the negative direction to stop the car.

We know that

v^2=u^2-2aS

0=20^2-2\times 2\times S

S=100 m

The total distance AD=AB + BC+ CD

AD=100 +200 + 100 m

AD=400 m.

The total distance will be 400 m.

4 0
3 years ago
Moving a magnet inside a coil of wire will induce a voltage in the coil. How can the voltage in the coil be increased?
mr_godi [17]
As the magnet is moved inside a coil of wire, the number of lines of magnetic field passing through the coil changes. Faraday stated that : it is the change in the number of field lines passing through the the coil of wire that induces emf in the loop. Specifically, it is the rate of change in the number of magnetic field lines passing through the loop that determines the induced emf. There is a term called magnetic flux same as electric flux, this magnetic flux can be a measure of the number of field lines passing through a surface. It is given by ( Φ=ΣB. dA. Where B is magnetic field and dA is small elementary area). The induced emf is given by (ξ = dΦ/dt). This equation states that THE MAGNITUDE OF THE INDUCED CURRENT IN A CIRCUIT IS EQUAL TO THE RATE AT WHICH THE MAGNETIC FLUX THROUGH THE CIRCUIT IS CHANGING WITH TIME. So more rapid you move the coil, more will be the change in flux and hence more emf will be produced. So option D is the correct answer. I hope this long description will help you out.
5 0
3 years ago
Read 2 more answers
A copper coin resting on a piece of cardboard is placed on a beaker as shown in the diagram below. When the cardboard is rapidly
Gelneren [198K]
The answer should be d) inertia
6 0
3 years ago
1. ¿Qué presión se ejerce sobre cada una de las cuatro patas de una mesa si su masa es de 20 kg y
mestny [16]
Tenemos.

Masa de la mesa = 20kg
Masa encima = 10kg
Masa total = 30kg
Area de cada pata = 20cm² = 20cm² * 1/10000cm² * 1m² =0,002m²

Presió(P)n que se ejerce sobre cada pata.

P =F/A
P = Masa por gravedad/A Masa = 30kg Gravedad =9,8m/s²
P =(30kg * 9,8m/s²)/0,002m²
P = 294kg * m/s²/0,002m² Pero kg *m/s² = Nw
P = 294Nw0,002m²
P = 147000 Nw/m² Pero Nw/m² = pa
p =1,47 * 10⁵ pa

Respuesta.
La presión que se ejerce sobre cada pata es de 1,47 * 10⁵pa
8 0
3 years ago
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