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3 years ago

11

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz t

one. The speed of sound is 343 m/s. What is the distance from speaker A to the first point on the line between the speakers where constructive interference occurs?

1 answer:

maw [93]3 years ago

3 0

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

$L_1=\frac{L-A}{2}$

where A = $\frac{Velocity ofthe sound (V)}{Frequency (F)}$

we have:

$L_1=\frac{L-\frac{V}{F} }{2}$

$L_1=\frac{6.69-\frac{343}{750} }{2}$

$L_1=\frac{6.69-0.457 }{2}$

$L_1=\frac{6.233 }{2}$

$L_1= 3.1165 m$

$L_1=3.117 m$

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m

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