Question

Determine the total force, in kn, on the bottom of a 100 × 50 m swimming pool. the depth of the pool varies linearly along its length from 1 m to 4 m.

Answer 1

Answer: The total force in the bottom of the swimming pool is 196,000 kilo-Newtons.

Explanation:

The force on the bottom of the swimming pool =F

$Force=Pressure\times Area$

Density of the water = $\rho =1000 kg/m^3$

Pressure at the bottom of the swimming pool=$\rho gh=1000 kg/m^3\times 9.8 m/s^2\times 4m$=39,200 Pascal[/tex]

Area at the bottom of the swimming pool :

Length of the base = 100 m

Width of the base = 50 m

= $100 m\times 50 m=5000 m^2$

$Force=Pressure\times Area=39,200 Pascal\times 5000 m^2=196,000,000 N=196,000 kilo-Newtons$

The total force in the bottom of the swimming pool is 196,000 kilo-Newtons.