A spaceship enters the solar system moving toward the Sun at a constant speed relative to the Sun. By its own clock, the time el
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Answer:
t=15.68 s
Explanation:
Given that
m = 1520 kg
P =75 KW
We know that
Power ,P = F .v
F=force
v=velocity
v= 100 km/h
v=27.77 m/s
75 x 1000 = F x 27.77
F= 2700.75 N
F= m a
m=mass
a=acceleration
2700.75 = 1520 x a
a=1.77 m/s²
time t given as
v= u + a t
27.77 = 0 + 1.77 x t
t=15.68 s
We can solve for the acceleration by using a kinematic equation. First we should identify what we know so we can choose the correct equation.
We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time of 6 s. We and looking for acceleration (a) in m/s^2.
The following equation has everything we need:
So plug in the known values and solve for a:
0 = 24 + 6a
-24 = 6a
a = -4 m/s^2
We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time of 6 s. We and looking for acceleration (a) in m/s^2.
The following equation has everything we need:
So plug in the known values and solve for a:
0 = 24 + 6a
-24 = 6a
a = -4 m/s^2