If a 2 kg ball is moving at 6 m/s to the right and then hits a wall and bounces back at - 4 m/s (left), what is the change in mo
1 answer:
Answer:
The change in momentum (in kg*m/s)
Explanation:
The change in momentum is equal to
Final Momentum - Initial Momentum
As we know
Momentum is equal to the product of mass and velocity
M = m * v
Thus, change in momentum
here m1 = m2 = 2 Kg
Substituting the given values in above equation we get -
kg m/s
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where:
F - force
m - mass
a - acceleration
We transform this formula to get a:
Answer:
11,890
Explanation:
First we need to know what is considered a significant figure.
A significant figure is a value that is not a zero at the start OR end of a value.
Which means, the 0 in the value of 90 or 0.363 are not considered a significant figure.
The 0 in the value of 3056 is considered a significant figure.
So from the table, we can deduce:
0.275 has 3 significant figures
750 has 2 significant figures
has 3 significant figures.
11,890 has 4 significant figures.
320,050 has 5 significant figures.
So from the above, we can already see the answer.
Answer:
Explanation:
We are given that
Atomic number=2
We have to find the total negative charge on the electrons in one mole of Helium.
We know that atomic number=Proton number
Proton number=Number of electrons=2
Number of electrons in Helium=2
1 mole of Helium= atoms
We know that q=ne
Where n =Number of fundamental units
e=Charge on electron
1 e=
Using the formula
Total negative charge in 1 mole=
Hence, the total negative charge on the electrons in 1 mole of Helium=