Question

If a 2 kg ball is moving at 6 m/s to the right and then hits a wall and bounces back at - 4 m/s (left), what is the change in momentum (in kg*m/s)?

Answer 1

Answer:

The change in momentum (in kg*m/s) $= 20$

Explanation:

The change in momentum is equal to

Final Momentum - Initial Momentum

As we know

Momentum is equal to the product of mass and velocity

M = m * v

Thus, change in momentum

$m_2v_2 - m_1v_1$

here m1 = m2 = 2 Kg

Substituting the given values in above equation we get -

$2 * 6 -( 2 *-4)\\12 + 8 = 20$kg m/s