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Anarel [89]
3 years ago
6

A machine has an efficiency of 80% how much work must be done on the machine so to make it do 50000 J of outfit work

Physics
1 answer:
katrin [286]3 years ago
6 0
With efficiency of 80%, the machine outputs 50000 J. The input to the machine should represent 100%.

If
80% --- 50000 J
100% --- ?? J

Solution:
Input work = (100/80)*500000 J = 62500 J
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At the train station, you notice a large horizontal spring at the end of the track where the train comes in. This is a safety de
xxMikexx [17]

Answer:

  v₀ = 9,798 ft / s

Explanation:

We can solve this problem with kinematics in one dimension, when the train stops the speed is zero, the acceleration is negative so that the train stops. Let's use the equation

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         v = 0

         v₀ = √2 a d

In the problem it indicates that the acceleration is g / 2, we substitute

         v₀ = √2 (g / 2) d

Let's calculate

         v₀ = √ 2 32/2 3 = √32 3

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8 0
4 years ago
Where could you hear a sonic boom
ExtremeBDS [4]
Answer

A sonic boom is a continuous effect that occurs while the object is travelling at supersonic speeds.
7 0
4 years ago
A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 5.0 km/h
Ratling [72]

Answer

given,

time  = 10 s

ship's speed = 5 Km/h

F = m a

a is the acceleration and m is mass.

In the first case

F₁=m x a₁

where a₁ =  difference in velocity / time

F₁ is constant acceleration is also a constant.

Δv₁ = 5 x 0.278

Δv₁ = 1.39 m/s

a_1=\dfrac{1.39}{10}

a₁ = 0.139 m/s²

F₂ =m x a₂

F₃ = F₂ + F₁

Δv₃ = 19 x 0.278

Δv₃ = 5.282 m/s

a₃=Δv₂ / t

a_3=\dfrac{5.282}{10}

a₃ = 0.5282 m²/s

m a₃=m a₁ + m a₂

a₃ = a₂ + a₁

0.5282 = a₂ + 0.139

a₂=0.3892 m²/s

F₂ = m x 0.3892...........(1)

F₁ = m x 0.139...............(2)

F₂/F₁

ratio = \dfrac{0.3892}{0.139}

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6 0
4 years ago
A mass executes SHM at the end of a light spring. (a) What fraction of the total energy of the system is potential and what frac
PolarNik [594]

Answer:

Explained

Explanation:

A) The total energy of the system is defined by the energy at maximum amplitude, which we'll call A. At that point, the energy of the system is

E = 1/2×m×A^2;

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So at x=1/2A,

the potential energy of the system is 1/8×m×A^2

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B) (i) Doubling the maximum amplitude will quadruple the total energy:

E= \frac{1}{2}m(2A)^2

(ii) Doubling the maximum amplitude will double the maximum velocity

\frac{1}{2}m(2A)^2= \frac{1}{2}mV^2

(iii) Doubling the maximum amplitude will double the maximum acceleration: m×a = -k(2A)

(iv) Doubling the maximum amplitude leaves the period unchanged:

T= 2\pi\sqrt{\frac{m}{k} }

(neither m nor k has changed).

6 0
3 years ago
When a molecule absorbs an infrared photon it contributes to the ________energy of that molecule.
Tpy6a [65]

Answer: INFRARED ENERGY

5 0
4 years ago
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