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Anarel [89]
3 years ago
6

A machine has an efficiency of 80% how much work must be done on the machine so to make it do 50000 J of outfit work

Physics
1 answer:
katrin [286]3 years ago
6 0
With efficiency of 80%, the machine outputs 50000 J. The input to the machine should represent 100%.

If
80% --- 50000 J
100% --- ?? J

Solution:
Input work = (100/80)*500000 J = 62500 J
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