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Anarel [89]
3 years ago
6

A machine has an efficiency of 80% how much work must be done on the machine so to make it do 50000 J of outfit work

Physics
1 answer:
katrin [286]3 years ago
6 0
With efficiency of 80%, the machine outputs 50000 J. The input to the machine should represent 100%.

If
80% --- 50000 J
100% --- ?? J

Solution:
Input work = (100/80)*500000 J = 62500 J
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Joan wants to take a 30.0N object up to the 3rd floor of her office building,which is 10m above the ground floor.It is too big t
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P=W/t
P=F×s/t
P=30×10/5= 60 W
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3 years ago
If velocity is 0.2m/s, what is the kinetic energy?
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\huge\boxed{♧ \: \mathfrak{ \underline{Answer} \: ♧}}

we know,

\boxed{kinetic  \:  \: energy =  \frac{1}{2} m {v}^{2} }

So,

\longmapsto \dfrac{1}{2}  \times 10 \times 0.2 \times 0.2

\longmapsto0.2 \: joules

3 0
3 years ago
the moderate temperatures of islands throughout the world has much to do with water's vast supply of internal energy. high evapo
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High specific heat of the water. Option (c)

What is Specific heat?

The amount of heat required to increase the temperature of one gram of a substance by one degree Celsius is referred to as the substance's specific heat. Typically, calories or joules are used per gram and degree Celsius when referring to the units of specific heat.

The moderate temperature of islands has much to do with the water's high specific heat. The typical off-water is more significant than this clear land or soil. Due to this fact, water absorbs and releases eat more slowly. In comparison to the land.

Hence, the water has high specific heat.

To learn more about specific heat the link is given below:

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3 0
1 year ago
A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a lar
horrorfan [7]

Answer:

W= 4.89 KJ

Explanation:

Lets take

temperature of hot water T₁ = 100⁰C

T₁ = 373 K

Temperature of cold ice T₂= 0⁰C

T₂ = 273 K

The latent heat of ice LH= 334 KJ

The heat rejected by the engine Q= m .LH

Q₂= 0.04 x 334

Q₂= 13.36 KJ

Heat gain by engine = Q₁

For Carnot engine

Q_1=\dfrac{T_1}{T_2}Q_2

Q_1=\dfrac{373}{273}\times 13.36

Q₁  = 18.25 KJ

The work W= Q₁  - Q₂

W= 18.25 - 13.36 KJ

W= 4.89 KJ

7 0
3 years ago
Read 2 more answers
How many times higher could an astronaut jump on the Moon than on Earth if his takeoff speed is the same in both locations (grav
JulsSmile [24]

Answer:

maximum height on moon is 6 times more than the maximum height on Earth

Explanation:

Let the Astronaut has its maximum speed by which he can jump is "v"

now for the maximum height that it can jump is given as

v_f^2 - v_i^2 = 2 aH

now from above equation we will have

0 - v^2 = 2(-g)H

now we have

H = \frac{v^2}{2g}

now if Astronaut jump on the surface of moon with same speed

then we know that the acceleration of gravity on surface of moon is 1/6 times the gravity on earth

so at surface of moon we have

0 - v^2 = 2(-g/6) H

now we have

H = \frac{6v^2}{2g}

so maximum height on moon is 6 times more than the maximum height on Earth

8 0
3 years ago
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