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3 years ago

A machine has an efficiency of 80% how much work must be done on the machine so to make it do 50000 J of outfit work

1 answer:

6 0

With efficiency of 80%, the machine outputs 50000 J. The input to the machine should represent 100%.

If
80% --- 50000 J
100% --- ?? J

Solution:
Input work = (100/80)*500000 J = 62500 J

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a rocket of mass 100,000 kg undergoes an acceleration of 2m/s2. show the net force acting on it is 200,000

just olya [345]

M= 100000 kg
a= 2m/s²

Use Newton's second law:
F=ma=100000kg • 2 m/s²
= 200000 N

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3 years ago

Answer and mark you as brainliest <br> it's that easy

Oduvanchick [21]

Answer:

$t=\frac{v-u}{a}$

b) 35m/s

c) 0

d) -35m/s

e) Velocity is decreasing.

f) 70 seconds

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3 years ago

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Two balls of mass 0.09 kg hang on strings attached to the same point on the ceiling. The balls are given charges Q that cause th

telo118 [61]

Answer:

Q = 6.33μC

Explanation:

To find the value of the charge Q you take into account both gravitational force and electric force over each ball. By symmetry you can use the fact that both balls experiences the same forces. Hence you only take into account the forces for one ball for the x component and y component:

$-Mg+Tcos\theta=0\\\\F_e-Tsin\theta=0$

M: mass of the ball = 0.09kg

T: tension of the string

F_e: electric force between charges

angle = 45°

The electric force is given by:

$F_e=k\frac{Q^2}{r^2}$

Q: charge of the balls

r: distance between balls = 2m

You divide both equation in order to eliminate the tension T:

$tan\theta=\frac{F_e}{Mg}=k\frac{Q^2}{Mgr^2}$

By doing Q the subject of the formula and replacing you obtain:

$Q=\sqrt{\frac{tan\theta Mgr^2}{k}}=\sqrt{\frac{tan45\°(0.09kg)(2m)^2}{(8.89*10^{9}Nm^2/C^2)}}=6.33*10^{-6}C=6.33\mu C$

hence, the charge of the balls is 6.33μC

4 0

3 years ago

The terminal speed of a sky diver is 130 km/h in the spread-eagle position and 326 km/h in the nosedive position. Assuming that

SIZIF [17.4K]

Answer:

$\frac{A_{slow} }{A_{fast} }=6.2885$

Explanation:

Given data

Terminal velocity for spread eagle position vt=130 km/h

Terminal velocity for nosedive position vt=326 km/h

The terminal speed of the diver is given by

$v_{t}=\sqrt{\frac{2mg}{CpA} }$

Therefore the area is given by

$A=\frac{2mg}{Cp(v_{t})^{2} }\\$

Since everything else is constant in the two dives except for the terminal velocity, the ratio between the area in the slow position to the area in the fast position is

$\frac{A_{slow} }{A_{fast} }=\frac{326^{2} }{130^{2} }\\\frac{A_{slow} }{A_{fast} }=6.2885$

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3 years ago

A SMALL cup of tea has water inside that is very hot, about 80 degrees Celsius. A LARGE bathtub has water inside it that is warm

Artist 52 [7]

Answer:

the water in the tea cup

Explanation:

Kinetic energy is the energy an object or particles possesses as a result of motion.

Liquid in higher temperature possesses more kinetic energy than liquid with lower temperature

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3 years ago