( 8.10) x 10^4 J = ½(1010kg)V²
<span>......................= 505V² </span>
<span>( 8.10) x 10^4 J =[(.0505) x 10^4] V² ........<==10^4 cancels </span>
<span>8.10 = .0505 V² </span>
<span>.........______ </span>
<span>V = ²√ 160.4 </span>
<span>V= 12.6 m/s </span>
<span>(that's 12.6m/sec(1km/1000m)(3600secs/1hr) = 45.36kph) </span>
<span> my diagram is wrong, it is just an ordinary car, </span>
Answer:
1)31/3Ω
2)18/31A
3)4.06V
Explanation:
According to the diagram and 10 Ω resistors are parallel to each other, parallel resistor can be calculated using the formula below
1/R= 1/R1 + 1/R2
But we know R1= 5 Ω and R2= 10 Ω
1/R= 1/5 + 1/10
R= 10/3 Ω
=3.33 Ω
Then if we follow the given figure, 10/3 Ω and 7Ω are now in series then
Req = 10/3 +7
Req= 31/3 Ω
Therefore, equivalent resistance = 31/3 Ω
According to ohms law we know that V= IR
Then I= V/R
Where I= current
R= resistance
V= voltage
I= 6/(31/3)
I= 18/31A
We can now calculate the voltage accross the resistor which is
V=(18/31)× 7
V=4.06V
Therefore, the voltage accross the 7 ohm resistor is 4.06V
CHECK THE FIQURE AT THE ATTACHMENT
Answer:
The average power developed by a motor is 4905 Watts.
Explanation:
The average power is given by:

Where:
W: is the work
t: is the time = 8.0 s
First, let's find the work:

Where:
F: is the force
d: is the displacement = 10.0 m
The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

Hence, the average power is:
Therefore, the average power developed by a motor is 4905 Watts.
I hope it helps you!
Potential difference required in an electron microscope to give an electron wavelength of 4. 5 nm will be 0.063 V.
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other is called potential difference.
The wavelength of an electron is calculated for a given energy (accelerating voltage) by using the de Broglie relation between the momentum p and the wavelength λ of an electron
lambda = 4.5 nm = 4.5 *
m
h =
J s
e = 1.6 *
C
m = 9.1 *
kg
Energy = eV
lambda = h /
= h /
=
/ (2m (eV))
V =
/ (2 m e
)
V =
/ 2 * 9.1 *
* 1.6 *
* 
V = 0.063 V
To learn more about wavelength of an electron here
brainly.com/question/17295250
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