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adell [148]
3 years ago
13

What happens when the object is placed at F? Explain your answer.

Physics
2 answers:
Alla [95]3 years ago
7 0

Answer:

No image will be formed because the rays will not converge to or diverge from a common point.

sp2606 [1]3 years ago
6 0

Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.

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Helen is driving her car if the kinetic energy of the car is 8.10 E4 J and the mass of the car and its contents is 1010 kg Helen
larisa86 [58]
( 8.10) x 10^4 J = ½(1010kg)V² 
<span>......................= 505V² </span>
<span>( 8.10) x 10^4 J =[(.0505) x 10^4] V² ........<==10^4 cancels </span>
<span>8.10 = .0505 V² </span>
<span>.........______ </span>
<span>V = ²√ 160.4 </span>

<span>V= 12.6 m/s </span>

<span>(that's 12.6m/sec(1km/1000m)(3600secs/1hr) = 45.36kph) </span>
<span> my diagram is wrong, it is just an ordinary car, </span>
6 0
3 years ago
For the electric circuit given below, calculate: 3 (i) the equivalent resistance of the circuit, (ii) the total current drawn fr
Daniel [21]

Answer:

1)31/3Ω

2)18/31A

3)4.06V

Explanation:

According to the diagram and 10 Ω resistors are parallel to each other, parallel resistor can be calculated using the formula below

1/R= 1/R1 + 1/R2

But we know R1= 5 Ω and R2= 10 Ω

1/R= 1/5 + 1/10

R= 10/3 Ω

=3.33 Ω

Then if we follow the given figure, 10/3 Ω and 7Ω are now in series then

Req = 10/3 +7

Req= 31/3 Ω

Therefore, equivalent resistance = 31/3 Ω

According to ohms law we know that V= IR

Then I= V/R

Where I= current

R= resistance

V= voltage

I= 6/(31/3)

I= 18/31A

We can now calculate the voltage accross the resistor which is

V=(18/31)× 7

V=4.06V

Therefore, the voltage accross the 7 ohm resistor is 4.06V

CHECK THE FIQURE AT THE ATTACHMENT

3 0
3 years ago
What is the average power developed by a motor as it lifts a 400.-kilogram mass at constant speed through a vertical distance of
Tomtit [17]

Answer:

The average power developed by a motor is 4905 Watts.

Explanation:

The average power is given by:

P = \frac{W}{t}

Where:

W: is the work

t: is the time = 8.0 s

First, let's find the work:

W = F*d

Where:

F: is the force

d: is the displacement = 10.0 m

The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

F = mg = 400 kg*9.81 m/s^{2} = 3924 N

Hence, the average power is:

P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W                    

Therefore, the average power developed by a motor is 4905 Watts.

I hope it helps you!                  

3 0
3 years ago
POR FAVOR AYUDENME A COMLETARLO
Zigmanuir [339]

Answer:

English please?

Explanation:

8 0
3 years ago
What potential difference is required in an electron microscope to give an electron wavelength of 4. 5 nm?
Lorico [155]

Potential difference required in an electron microscope to give an electron wavelength of 4. 5 nm will be 0.063 V.

The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other is called potential difference.

The wavelength of an electron is calculated for a given energy (accelerating voltage) by using the de Broglie relation between the momentum p and the wavelength λ of an electron

lambda = 4.5 nm = 4.5 * 10^{-9} m

h = 6.626 * 10^{-34}  J s

e = 1.6 * 10^{-19} C

m = 9.1 * 10^{-31} kg

Energy = eV

lambda = h / \sqrt{2mE} = h / \sqrt{2m(eV)}

(lambda)^{2} = h^{2} / (2m (eV))

V = h^{2} / (2 m e  (lambda)^{2} )

V  =  (6.626 * 10^{-34} )^{2} /  2 * 9.1 * 10^{-31} *  1.6 * 10^{-19}  * (4.9 * 10^{-9}) ^{2}

V = 0.063 V

To learn more about wavelength of an electron  here

brainly.com/question/17295250

#SPJ4

7 0
2 years ago
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