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Lostsunrise [7]
4 years ago
14

A pump of power 1500W is used for 5 mins the energy supplied by the pump is​

Physics
1 answer:
Anika [276]4 years ago
7 0

Answer:

300W

Explanation:

from my years in middle school, i have learned the equation is energy =power*time is 300W

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Niobium metal becomes a superconductor (with zero electrical resistance) when cooled below 5.1 K. The permeabilty of free space
katovenus [111]

Answer:

687.5 A

Explanation:

We are given that

\mu_0=1.25664\times 10^{-6}N/A^2

Magnetic field,B=0.11 T

Diameter,d=2.5mm

Radius,r=\frac{d}{2}=\frac{2.5}{2}mm=1.25\times 10^{-3} m

1mm=10^{-3} m

We know that current in coil

I=\frac{2\pi rB}{\mu_0}

Substitute the values

I=\frac{2\pi\times 1.25\times 10^{-3}\times 0.11}{1.25664\times 10^{-6}}

I=687.5 A

8 0
3 years ago
What is the new pressure of 150 ml of a gas that is compressed to 50 ml when the original pressure was 3.0 atm and the temperatu
Firlakuza [10]

Answer: 9.0 atm

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=3.0atm\\V_1=150mL\\P_2=?mmHg\\V_2=50mL

Putting values in above equation, we get:

3.0\times 150mL=P_2\times 50mL\\\\P_2=9.0atm

Thus new pressure of 150 ml of a gas that is compressed to 50 ml is 9.0 atm

5 0
4 years ago
A 7.3 kg bowling ball would require how much force if you use a broom to
il63 [147K]

Answer:

0.219N

Explanation:

Given data

mass= 7.3kg

acceleration= 0.03m/s^2

We know that

F=ma

substitute

F= 7.3*0.03

F= 0.219N

Hence the applied force is 0.219N

7 0
3 years ago
Savanna regions developed during the Triassic period.
stich3 [128]
The answer is : true
5 0
1 year ago
A novelty golf ball of mass m is launched with an initial velocity v0 = (25i + 13j) m/s and then follows a parabolic trajectory.
SVEN [57.7K]

Explanation:

(a)

The initial vertical velocity is 13 m/s.  At the maximum height, the vertical velocity is 0 m/s.

v = at + v₀

0 = (-9.8) t + 13

t ≈ 1.33 s

(b)

Immediately prior to the explosion, the ball is at the maximum height.  Here, the vertical velocity is 0 m/s, and the horizontal velocity is constant at 25 m/s.

v = √(vx² + vy²)

v = √(25² + 0²)

v = 25 m/s

(c)

Momentum is conserved before and after the explosion.

In the x direction:

m vx = ma vax + mb vbx

m (25) = (⅓ m) (0) + (⅔ m) (vbx)

25m = (⅔ m) (vbx)

25 = ⅔ vbx

vbx = 37.5 m/s

And in the y direction:

m vy = ma vay + mb vby

m (0) = (⅓ m) (0) + (⅔ m) (vby)

0 = (⅔ m) (vby)

vby = 0 m/s

Since the vertical velocity hasn't changed, and since Fragment B lands at the same height it was launched from, it will have a vertical velocity equal in magnitude and opposite in direction as its initial velocity.

vy = -13 m/s

And the horizontal velocity will stay constant.

vx = 37.5 m/s

The velocity vector is (37.5 i - 13 j) m/s.  The magnitude is:

v = √(vx² + vy²)

v = √(37.5² + (-13)²)

v ≈ 39.7 m/s

7 0
4 years ago
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