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3 years ago

8

A woman using a compass and a map walks 132 east of north for 6 km

2 answers:

REY [17]3 years ago

8 0

————-132 x 6 = 792————

ANEK [815]3 years ago

7 0

If she walks 132 and 6 you do 132 x 6 = 792

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Synchronous communications satellites are placed in a circular orbit that is 3.59 107 m above the surface of the earth. What is

suter [353]

Answer: $0.223 m/s^{2}$

Explanation:

We can solve this with the Law of Universal Gravitation and knowing the acceleration due gravity $g$ of an object above the surface of the planet decreases with the distance (height) of this object from the center of the planet.

Well, according to the law of universal gravitation:

$F=G\frac{m_{E}m}{r^2}$ (1)

Where:

$F$ is the module of the force exerted between both bodies

$G=6.67(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the gravitational constant

$m_{E}=5.98(10)^{24} kg$ is the mass of the Earth

$m$ are the mass of each communications satellite

$r=R_{E}+h$ is the distance between the center of the Earth and the satellite

$R_{E}=6.38(10)^{6} m$ is the radius of the Earth

$h=3.59(10)^{7} m$ is the height of the satellite, measured from the Earth's surface

On the other hand, we know according to <u>Newton's 2nd law of motion:</u>

$F=mg$ (2)

Combining (1) and (2):

$G\frac{m_{E}m}{r^2}=mg$ (3)

Isolating $g$ :

$g=\frac{G M_{E}}{r^2}$ (4)

Remembering $r=R_{E}+h$ :

$g=\frac{G M_{E}}{(R_{E}+h)^2}$ (5)

$g=\frac{(6.67(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24} kg)}{(6.38(10)^{6} m+3.59(10)^{7} m)^2}$

Finally:

$g=0.223 m/s^{2}$

5 0

3 years ago

The surface tension of isopropanol in air has a value of 23.00 units and the

Y_Kistochka [10]

Answer:

It's A & C

Explanation:

:p

7 0

3 years ago

Read 2 more answers

What is the momentum of a 12 kg condor flying at 6 m/s?

rusak2 [61]

Answer:

72

Explanation:

Formula

$p=mv\\=12*6\\=72$

5 0

3 years ago

The record of an earthquake obtained from a seismic instrument is a(n) ________.

serious [3.7K]

<span>The record of an earthquake obtained from a seismic instrument is a </span>
SEISMOGRAM

6 0

3 years ago

A cork has weight mg and density 25% of water’s density. A string is tied around the cork and attached to the bottom of a water-

yuradex [85]

Answer:

Explanation:

Given

Density of Cork $\rho _c=0.25\rho _{water}$

Considering V be the volume of Cork

Buoyant Force will be acting Upward and Weight is acting Downward along with T

Since density of water is more than cork therefore Cork will try to escape out of water but due to tension it will not

we can write as

$\rho _{water}Vg-\rho _Cvg-T=0$

where T=tension

Thus Tension T is

$T=Vg(\rho _{water}-\rho _c)$

Taking $\rho _c$ common

$T=\rho _cVg(\frac{\rho _{water}}{\rho _c}-1)$

$T=mg(\frac{\rho _{water}}{\rho _c}-1)$

$T=mg(4-1)$

$T=3mg$

4 0

3 years ago