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3 years ago

A woman using a compass and a map walks 132 east of north for 6 km

Physics

2 answers:

REY [17]3 years ago

8 0

————-132 x 6 = 792————

ANEK [815]3 years ago

7 0

If she walks 132 and 6 you do 132 x 6 = 792

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Evaluate ( 64800 ms ) 2 to three significant figures and express the answer in Si units. Express your answer using three signifi

Sergeu [11.5K]

Answer:

42.0×10² second²

Explanation:

Here, time is given in milisecond

(64800 ms)²

= 4199040000 ms²

The SI unit is seconds

1 second = 1000 milisecond

$1\ milisecond=\frac{1}{1000}\ second$

$\\\Rightarrow 1\ milisecond^2=\left(\frac{1}{1000}\right)^2\ second^2$

$4199040000\ ms^2=4199040000\times \left(\frac{1}{1000}\right)^2\ second^2=4199.04\ second^2$

42.0×10² second²

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3 years ago

During a softball game, a player running from second base to third base reaches a speed

andrey2020 [161]

Answer: I would say it would be 3.9

but i believe there is something missing shorty.

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3 years ago

What would happen to the amount of matter on earth if mass were not conserved during changes of state?

attashe74 [19]

<span>earth would be thrown off its balance and nature would be in danger of too many resources and not enough resources </span>

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3 years ago

Read 2 more answers

0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained a

klio [65]

Answer:

The boiling point temperature of this substance when its pressure is 60 psia is 480.275 R

Explanation:

Given the data in the question;

Using the Clapeyron equation

$(\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}$

$(\frac{dP}{dT} )_{sat } = \frac{\frac{H_{fg}}{m} }{T\frac{V_{fg}}{m} }$

where $h_{fg$ is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu

T is the temperature ( 15 + 460 )R

m is the mass of water ( 0.5 Ibm )

$V_{fg$ is specific volume ( 1.5 ft³ )

we substitute

$(\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5})$ / $( (15+460)\frac{1.5}{0.5})$

$(\frac{dP}{dT} )_{sat } =$ 272.98 Ibf-ft²/R

Now,

$(\frac{dP}{dT} )_{sat } =$ $(\frac{P_2 - P_1}{T_2 - T_1})_{sat$

where P₁ is the initial pressure ( 50 psia )

P₂ is the final pressure ( 60 psia )

T₁ is the initial temperature ( 15 + 460 )R

T₂ is the final temperature = ?

we substitute;

$T_2$ $= ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}$

$T_2 = 475 + 5.2751\\$

$T_2 =$ 480.275 R

Therefore, boiling point temperature of this substance when its pressure is 60 psia is 480.275 R

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3 years ago

Who is wwe universal champion

mina [271]

Answer:

Roman reigns

Explanation:

is the wwe universal hampion

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