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Alex17521 [72]
3 years ago
15

a 2 meters tall person is located 5 meters from a camera lens (camera lens are convex lenses). the lens has a focal length of 35

millimeters. do not forget to convert millimeters to meters before subbing into the equation. find the distance where the image would appear.
Physics
1 answer:
ki77a [65]3 years ago
3 0
Sorry that you got your answer late but the answer is 0.035m
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A car in front of the school goes from rest to 27 m/s in 3.0 seconds. What is its acceleration (assuming
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The answer is 13.5 because 27÷3.0=13.5

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The potential difference between the plates of an ideal air-filled parallel-plate capacitor with a plate separation of 6.0 cm is
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Answer:

1000 N/C

Explanation:

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The electric field between the plates is given by

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A 0.8 g object is placed in a 534 N/C uniform electric field. Upon being released from rest, it moves 12 m in 1.2 s. Determine t
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Explanation:

It is given that,

Mass of the object, m = 0.8 g = 0.0008 kg

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Distance, s = 12 m

Time, t = 1.2 s

We need to find the acceleration of the object. It can be solved as :

m a = q E.......(1)

m = mass of electron

a = acceleration

q = charge on electron

"a" can be calculated using second equation of motion as :

s=ut+\dfrac{1}{2}at^2

s=0+\dfrac{1}{2}at^2

a=\dfrac{2s}{t^2}

a=\dfrac{2\times 12\ m}{(1.2\ s)^2}

a = 16.67 m/s²

Now put the value of a in equation (1) as :

q=\dfrac{ma}{E}

q=\dfrac{0.0008\ kg\times 16.67\ m/s^2}{534\ N/C}

q = 0.0000249 C

or

q=2.49\times 10^{-5}\ C

Hence, this is the required solution.

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