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Kaylis [27]
3 years ago
13

Can someone do this assignment for me about force

Physics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

Newtons 3sd law

Force = mass × acceleration

3rd photo about momentum

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True or false question scientists can predict when an earthquake will occur
Tanya [424]

Answer:

False

Explanation:

Neither the USGS nor any other scientists have ever predicted a major earthquake. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.

6 0
3 years ago
What happens overtime to rocks that are stressed
malfutka [58]

Answer:

Stress is the force applied to an object. In geology, stress is the force per unit area that is placed on a rock. Four types of stresses act on materials.

A deeply buried rock is pushed down by the weight of all the material above it. Since the rock cannot move, it cannot deform. This is called confining stress.

Compression squeezes rocks together, causing rocks to fold or fracture (break) (Figure below). Compression is the most common stress at convergent plate boundaries.

Explanation:

4 0
3 years ago
silicon is the principal component of glass and has properties of both metals and non-metals. this makes silicon A) Metal B) Non
Eddi Din [679]
Silicon is in fact a Metalloid. Comment if you need more info!
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5 0
3 years ago
A woman in a sprint race accelerates from rest to 8.7 m/s in 2.7 s. What is her displacement?​
Trava [24]

Answer:

23.49m

Explanation:

Distance =  velocity x time

8.7 x 2.7 = 23.49m

8 0
3 years ago
(a) What is the escape speed on a spherical asteroid whose radius is 500. km and whose gravitational acceleration at the surface
navik [9.2K]

Answer:

a) v= 1732.05m/s

b) d=250000m

c) v= 1414.214m/s

Explanation:

Notation

M= mass of the asteroid

m= mass of the particle moving upward

R= radius

v= escape speed

G= Universal constant

h= distance above the the surface

Part a

For this part we can use the principle of conservation of energy. for the begin the initial potential energy for the asteroid would be U_i =-\frac{GMm}{R}.

The initial kinetic energy would be \frac{1}{2}mv^2. The assumption here is that the particle escapes only if is infinetely far from the asteroid. And other assumption required is that the final potential and kinetic energy are both zero. Applying these we have:

-\frac{GMm}{R}+\frac{1}{2}mv^2=0   (1)

Dividing both sides by m and replacing \frac{GM}{R} by a_g R

And the equation (1) becomes:

-a_g R+\frac{1}{2} v^2=0   (2)

If we solve for v we got this:

v=\sqrt{2 a_g R}=\sqrt{2x3\frac{m}{s^2}x500000m}=1732.05m/s

Part b

When we consider a particule at this surface at the starting point we have that:

U_i=-\frac{GMm}{R}

K_i=\frac{1}{2}mv^2

Considering that the particle is at a distance h above the surface and then stops we have that:

U_f=-\frac{GMm}{R+h}

K_f=0

And the balance of energy would be:

-\frac{GMm}{R}+\frac{1}{2}mv^2 =-\frac{GMm}{R+h}

Dividing again both sides by m and replacing \frac{GM}{R} by a_g R^2 we got:

-a_g R+\frac{1}{2}v^2 =-\frac{a_g R^2}{R+h}

If we solve for h we can follow the following steps:

R+h=-\frac{a_g R^2}{-a_g R+\frac{1}{2}v^2}

And subtracting R on both sides and multiplying by 2 in the fraction part and reordering terms:

h=\frac{2a_g R^2}{2a_g R-v^2}-R

Replacing:

h=\frac{2x3\frac{m}{s^2}(500000m)^2}{2(3\frac{m}{s^2})(500000m)-(1000m/s)^2}- 500000m=250000m

Part c

For this part we assume that the particle is a distance h above the surface at the begin and start with 0 velocity so then:

U_i=-\frac{GMm}{R+h}

K_i=0

And after the particle reach the asteroid we have this:

U_f=-\frac{GMm}{R}

K_f=\frac{1}{2}mv^2

So the balance of energy would be:

-\frac{GMm}{R+h}=-\frac{GMm}{R}+\frac{1}{2}mv^2

Replacing again a_g R^2 instead of GM and dividing both sides by m we have:

-\frac{a_g R^2}{R+h}=-a_g R+\frac{1}{2}v^2

And solving for v:

a_g R-\frac{a_g R^2}{R+h}=\frac{1}{2}v^2

Multiplying both sides by two and taking square root:

v=\sqrt{2a_g R-\frac{2a_g R^2}{R+h}}

Replacing

v=\sqrt{2(3\frac{m}{s^2})(500000m)-\frac{2(3\frac{m}{s^2}(500000m)^2}{500000+1000000m}}=1414.214m/s

3 0
3 years ago
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