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user100 [1]
3 years ago
15

I need to know why the particles at the surface in the image below have surface tension while the particles below the surface do

not.

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
8 0
Jshshehnenebdhsns shdienwhsiansgbsuwhw
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Consider the cell pt | h2 (1 atm); h+ (? m) || hg2cl2(s); cl− (1 m) | hg 2 h+ + 2 e − → h2 e 0 = 0.00 v hg2cl2 + 2 e − → 2 hg +
Dmitry [639]

Answer:

1.39

Explanation:

[Hg2Cl2]= 1M

[H^+] = ????

E°cell= 0.35V

E= 0.268 V

Therefore E for the reaction must -0.082 V

n= 2 moles of electrons

From Nernst Equation:

E= E°cell- 0.0592/n log [Red]/[Ox]

0.0268= 0.35- 0.0592/2 log 1/[Ox]^2

-0.082= -0.0296 log 1/[Ox]^2

log 1/[Ox]^2= 0.082/0.0296

log 1/[Ox]^2= 2.77

1/[Ox]^2=Antilog (2.77)

[Ox]^2=1.698×10^-3

[Ox] = 0.0412 M

But pH= -log [H^+]= -log(0.0412)= 1.385

3 0
3 years ago
Read 2 more answers
Which is an example of chemical property? A. Rain freezing into hail. B. A rusty screw. C. Ice melting in a glass. D. Gas in the
Advocard [28]
A. because a chemical change is something that's changing
7 0
3 years ago
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1) H, + NH, &lt; -&gt; H +<br> NH4+
Goshia [24]
If this is balancing them its 4H+1NH —> 1H+NH4
8 0
3 years ago
How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°
kotykmax [81]

Answer:

\boxed {\boxed {\sf 1076.196 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

q=mc\Delta T

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

  • The change in temperature is the difference between the initial temperature to the final temperature.
  • The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
  • ΔT= final temperature - initial temperature
  • ΔT= 67°C - 23°C
  • ΔT= 44°C

Now we know all the values.

  • m= 26.3 g
  • c= 0.930 J/g °C
  • ΔT= 44°C

Substitute the values into the formula.

q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)

Multiply the first two numbers together. The units of grams cancel.

q= 24.459 \ J/ \textdegree C \times 44 \textdegree C

Multiply again. This time, the units of degrees Celsius cancel.

q=1076.196 \ J

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.

4 0
3 years ago
Convert 100mL to L. Show your work to receive full credit.
Ilya [14]

Answer:

100 ml = 0.1 L

I divided 100 by 1000 because 1000ml = 1L

3 0
3 years ago
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