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Andrews [41]
3 years ago
12

The constant-pressure specific heat of air at 25°C is 1.005 kJ/kg °C. Express this value in kJ/kg-K. J/g °C, kcal/kg-°C, and Btu

/lbm-°F.
Chemistry
1 answer:
SashulF [63]3 years ago
8 0

Answer:

Cp= 1.005 kJ/kg °C =  1.005 kJ/(kg*K) = 1.005 J/g°C = 4.206 J/g°C = 0.776 BTU/lb°F

Explanation:

for the specific heat

1) Cp= 1.005 kJ/kg °C * (1 °C/ 1 K) (temperature differences) = 1.005 kJ/(kg*K)

2) Cp= 1.005 kJ/kg °C * (1000 J/ kJ)* (1 kg/1000 gr) = 1.005 J/g°C

3) Cp= 1.005 kJ/kg °C * (4.186 kcal/kJ) = 4.206 J/g°C

4) Cp= 1.005 kJ/kg °C * (1 BTU/1.055 kJ)* (0.4535 kg/lb)*(1.8°C/°F)= 0.776 BTU/lb°F

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