The correct answer is:
electrons/second
Explanation:
5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:
Electrons per second = 
Answer:
- the coating’s index of refraction is 1.25
- the required thickness is 104.1667 nm
Explanation:
Given the data in the question;
Thickness of coating t = 100 nm
wavelength λ = 500nm
we know that refractive index is;
t = λ/4n
make n, the subject of formula
t4n = λ
n = λ / 4t
we substitute
n = 500 / ( 4 × 100 )
n = 500 / 400
n = 1.25
Therefore, the coating’s index of refraction is 1.25
2)
given that;
Index of refraction of the coating; n = 1.20
λ = 500 nm
thickness of coating t = ?
t = λ / 4n
we substitute
t = 500 / ( 4 × 1.2 )
t = 500 / 4.8
t = 104.1667 nm
Therefore, the required thickness is 104.1667 nm
When an electric current is flowing through a wire, there is a magnetic <em>field</em> produced. The lines of magnetic force are circles around the wire.
Answer:
= 3.36 mm
Explanation:
From Ohm's law,
(Voltage = Current * Resistance)

The geometric definition of resistance is

where
is the resistivity of the material,
and
are the length and cross-sectional area, respectively.


Since the wire is assumed to have a circular cross-section, its area is given by
where
is the diameter.


Resistivity of copper =
. With these and other given values,



Answer: B - 8
Explanation: 8 protons because number of protons is equal to number of atoms in the nucleus.