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frutty [35]
3 years ago
5

A guitar string is 0.620m long, and oscillates at 234Hz. What is the velocity of the waves in the string? m/s

Physics
1 answer:
9966 [12]3 years ago
3 0

Answer:

v = 72.54 m/s

Explanation:

We have,

Length of a guitar string is 0.62 m

Frequency of a guitar string is 234 Hz

For guitar string,

L=2\lambda\\\\\lambda=\dfrac{L}{2}\\\\\lambda=\dfrac{0.62}{2}\\\\\lambda=0.31\ m

The velocity of the wave in the string is given by :

v=f\lambda\\\\v=234\times 0.31\\\\v=72.54\ m/s

So, the velocity of the waves in the string is 72.54 m/s.

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A 5.00-a current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. copper has 8.5 * 1028 free ele
vlada-n [284]

The correct answer is: 3.125*10^{19} electrons/second

Explanation:

5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:

Electrons per second = n_e=\frac{5}{e}=\frac{5}{ 1.60\cdot 10^{-19}}=3.125*10^{19}

7 0
3 years ago
Read 2 more answers
8 points)Antireflection coating can be used on the eyeglasses to reduce the reflection of light: a) A 100nm thick coating is app
NemiM [27]

Answer:

- the coating’s index of refraction is 1.25

- the required thickness is 104.1667 nm

Explanation:

Given the data in the question;

Thickness of coating t = 100 nm

wavelength λ = 500nm

we know that refractive index is;

t = λ/4n

make n, the subject of formula

t4n = λ

n = λ / 4t

we substitute

n = 500 / ( 4 × 100 )

n = 500 / 400

n = 1.25

Therefore, the coating’s index of refraction is 1.25

2)

given that;

Index of refraction of the coating; n = 1.20

λ = 500 nm

thickness of coating t = ?

t = λ / 4n

we substitute

t = 500 / ( 4 × 1.2 )

t = 500 / 4.8

t = 104.1667 nm

Therefore, the required thickness is 104.1667 nm

4 0
3 years ago
when an electric current is flowing through a wire which of the following is also produced energy domain field force
qaws [65]

When an electric current is flowing through a wire, there is a magnetic <em>field</em> produced.  The lines of magnetic force are circles around the wire.

4 0
3 years ago
When the starter motor on a car is engaged, there is a 290 A current in the wires between the battery and the motor. Suppose the
Tema [17]

Answer:

33.6\times10^{-4}}\text{ m} = 3.36 mm

Explanation:

From Ohm's law,

V = IR (Voltage = Current * Resistance)

R = \dfrac{V}{I}

The geometric definition of resistance is

R = \rho\dfrac{l}{A}

where \rho is the resistivity of the material, l  and A are the length and cross-sectional area, respectively.

A = \rho\dfrac{l}{R}

A = \rho\dfrac{l\timesI}{V}

Since the wire is assumed to have a circular cross-section, its area is given by

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\pi\dfrac{d^2}{4} = \rho\dfrac{l\timesI}{V}

d = \sqrt{\dfrac{4\rho l I}{\pi\times V}}

Resistivity of copper = 1.68\times10^{-8}. With these and other given values,

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d = \sqrt{1128.43\times10^{-8}}

d = 33.6\times10^{-4} \text{ m}

5 0
3 years ago
Question 8 (1 point) How many protons are in an element with an atomic number of 8 and a mass number of 18? a 3 b 8 c 10 d 18
yarga [219]

Answer: B - 8

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6 0
3 years ago
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