Answer:
1 second
Explanation:
h = −16t² + 32t
When, h = 16
16 = −16t² + 32t
Divide each of the numbers by 16
1 = -1t² + 2t
Rearrange the equation
1t²-2t+1 = 0
Solving by the quadratic formula, we get

So, time taken by the dolphin to jump out of the water and touch the trainer's hand is 1 second.
Answer:
Explanation:
We have given charge on the particle 
Mass of the charge particle 
From energy of conservation kinetic energy will be equal to potential energy
So at point A

At point a velocity is zero
So 

At point B velocity will be 72 m/sec
So 

So 