The variation of water depth at spreading centers (ridges) controlled by isostasy as convective cooling cools the rocks much more effectively the than heat conduction.
<h3>What is convective heat transfer?</h3>
When heat transfer takes place between the two fluids in direct or indirect contact.
The lithosphere cools when it moves away from the ridge axis by sea floor spreading. The cooler rocks have low density, so the sea floor gets deeper as the lithosphere gets more dense.
Thus, the convective cooling cools the rocks much more effectively the than heat conduction.
Learn more about convective heat transfer
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Answer:
See explanations
Explanation:
Given that,
Electric field E=135V/m
Energy stored in 1m³of air=?
The energy stored in an electric field is given as
u = ½ εo E²
Where
U is the energy stored
εo is permissivity and it value is 8.85×10^-12C²/N..m²
And E is the electric field
Then,
U=½×8.85×10^-12×135²
U=8.06×10^-8J/m³
Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³
Answer:
D: 35 m/s
Explanation:
The bus is moving at a speed of 20 m/s.
Thus; v_bus = 20 m/s
Tennis ball thrown horizontally towards the front of the bus is given as 15 m/s.. Thus, v_ball = 15 m/s
No, due to the fact that the bus and the ball are moving at the same time, an observer will think the speed is the sum of that of the ball and the bus.
Thus, it will appear to an observer on the sidewalk that the speed is; v_bus + v_ball = 20 + 15 = 35 m/s
C) 15 J because it cannot gain energy or lose mass
Answer:
180 [J].
Explanation:
1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;
2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;
3) then the required work [W]:
W=mg*(h₂-h₁)=30*6=180 [J].
