A body travels at an initial speed of 2.5 m/s. Given a constant acceleration of 0.2 m/s 2 what is the speed of the body at time
1 answer:
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The combined momentum is 4000 kg m/s south
Explanation:
The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.
For this problem, we choose north as positive direction and south as negative direction.
The momentum of the first car travelling north is given by:
where
is the mass of the car
is its velocity
Substituting,
The momentum of the second car travelling south is given by:
where
is the mass of the car
is its velocity (negative because the car travels south)
Substituting,
And therefore, the combined momentum is
where the negative sign means the direction of the total momentum is south.
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Answer:
The force required to move the quarterback with linebacker is <u>1215 N</u>
Explanation:
Using Newton's second law, it is established that F = Ma
Where F is net force acting on the system, a is the acceleration and M is mass of the two object
Now consider both as a system, so net force acting on the system is
Substitute the given values in the above formula,
Force = 1215 N
<u>1215 N </u>is the force required to move the quarterback with linebacker.