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Eddi Din [679]
3 years ago
11

In order to rinse the system of exhaled C02 and meet the inspiratory flow rate requirements of infants placed on B-CPAP, the flo

w rate of humidified gas should be set at:_________.
Chemistry
1 answer:
LuckyWell [14K]3 years ago
3 0

Answer:

In order to rinse the system of exhaled CO2 and meet the inspiratory flow rate requirements of infants placed on B-CPAP, the flow rate of humidified gas should be set at:

A. 16 to 20 L/minute

B. 6 to10 L/minute

C. at least 15 L/minute

D. 11 to 15 L/minute

B. 6 to10 L/minute

Explanation:

Bubble CPAP is a non-invasive, external ventilation technique used for newborn babies with infant respiratory distress syndrome (IRDS). Continuous positive airway pressure (CPAP) is given to a spontaneously breathing newborn baby to preserve lung volumes during expiration

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Answer:

All living things are organized into groups by scientists as they are identified. Living things organized into particular groups have common characteristics. Overall, the reason scientists classify living things is to understand the relationships between different organisms

Explanation: Naruto

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H2 + Br2 → 2HBr If 2.23 g of hydrogen (H2) reacts completely, how many grams of hydrogen bromide (HBr) is formed? (mw Br=79.9) Q
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Answer:

The correct option is;

B) 179 g

Explanation:

The parameters given are;

Mass of H₂ that takes part in the reaction = 2.23 g

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n = \dfrac{Mass \ of \ hydrogen \ gas, \, H_2 }{Molar \ mass \ of  \, H_2 } = \dfrac{2.23}{2.016} = 1.106 \ moles

Chemical equation for the reaction;

H₂ + Br₂ → 2HBr

Given that one mole of H₂ reacts with one mole of Br₂ to produce two moles of HBr

1.106 mole of H₂ will react with 1.106 mole of Br₂ to produce 2 × 1.106 which is 2.212 moles of HBr

The molar mass, of HBr = 80.91 g/mol

The mass of HBr produced = Molar mass of HBr × Number of moles of HBr

The mass of HBr produced = 80.91 × 2.212 = 178.997 g ≈ 179 grams

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i would say B? Im sorry if im wrong

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