Answer:
The GCF is x²
Step-by-step explanation:
The equation in standard form would be,
All you have to do is move -2/7x to the other side.
Hope this helped
:D
It is not recommended that points be marked with X, let's marked with C(6,6)=(Xc,Yc)
The coordinates of the point C(Xc,Yc) which belongs to the line AB and divides line AB in a ratio m : n = 1 : 2 or m/n=1/2 are get it with following formula
Xc=(Xa+(m/n)Xb) / (1+(m/n)) and Yc=(Ya+(m/n)Yb) / (1+(m/n))
We have A(2,2)=(Xa,Ya) and B(14,14)=(Xb,Yb)
When we replace given coordinates we get
Xc=(2+(1/2)*14) / (1+(1/2)) = (2+7) /(3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Xc=6
Yc=(2+(1/2)*14) / (1+(1/2)) = (2+7) / (3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Yc=6
C(Xc,Yc)=(6,6)
Good luck!!!
Answer:
y = 1/2x +4
Step-by-step explanation:
You are given the slope (m) of the line and a point, and asked for slope-intercept form:
y = mx +b . . . . . . . line with slope m and y-intercept b
The value of the intercept, b, can be found from the point by rearranging this equation to ...
b = y -mx
b = 1 -1/2(-6) = 4 . . . . using x=-6, y=1
Then the equation of the line with m=1/2 and b=4 is ...
y = 1/2x +4
Answer:
Quadratic
Step-by-step explanation:
It's not linear because the speed of the penny is not<u> </u>constant.
It is not exponential because the speed does not continuously increase at a faster rate.
It is Quadratic because the penny will increase speed as you throw it up into the air. Once it reaches its "high point" it's speed hits 0, which is the origin of the quadratic equation. Then the speed increases faster and faster as it falls.
