Your answer would be C9H16
Answer:
The
of a substrate will be "10 μM".
Explanation:
The given values are:

![[Substract] = 40 \ \mu M](https://tex.z-dn.net/?f=%5BSubstract%5D%20%3D%2040%20%5C%20%5Cmu%20M)

Reaction velocity, 
As we know,
⇒ ![Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}](https://tex.z-dn.net/?f=Vo%3D%5Cfrac%7BK_%7Bcat%7D%5BE_%7Bt%7D%5D%5BS%5D%7D%7BK_%7Bm%7D%2B%5BS%5D%7D)
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
On subtracting "40" from both sides, we get
⇒ 
⇒ 
Answer:
The answer is Ionization energy.
Explanation:
Ionization Energy. The ionization energy tends to increase as one moves from left to right across a given period or up a group in the periodic table.
Answer:
a. 123.9°C
b.
c.
Explanation:
Hello, I'm attaching a picture with the numerical development of this exercise.
a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.
b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.
c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.
** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.
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Answer: The value of
for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.
Explanation:
Given: Moles of solute = 0.793 mol
Mass of solvent = 0.758

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Now, the values of
is calculated as follows.

where,
i = Van't Hoff factor = 1 (for chloroform)
m = molality
= molal boiling point elevation constant
Substitute the values into above formula as follows.

Thus, we can conclude that the value of
for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.