2.13x10^24 is the answer.
Answer:
It is basic.
Explanation:-
Given hydrogen ion concentration [H+] = 1×10^-12
Using the formula
pH = - log [H+]
= - log [ 1 x 10^-12]
= 12
Since the pH is more than 7, the chemical is basic
The percentage of the sulfur (S) in the compound CuSO₄ is 20.1 %.
<h3>What is the mass percentage?</h3>
The percentage of an element in a compound can be determined as the number of parts by mass of that element present in 100 parts by mass of the given compound.
First, calculate the molecular mass of the given compound by the addition of the atomic masses of all the present elements in the molecular formula. Then, the percentage of the elements can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.
Given, the atomic mass of copper, sulfur, and oxygen is 63.55 g, 32.07 g, and 16.0g respectively.
The molecular mass of CuSO₄ = 63.55 + 32.07 + 4(16.0) = 159.62 g
The mass percentage of the sulphur = (32.07/159.62) × 100 = 20.1 %
Therefore, the mass percentage of the sulfur is equal to 20.1 %.
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Answer:
3.5 yrs
Explanation:
If a sample has decayed to 25%, this means 2 half-lives have passed. We are given this is equal to 7 yrs, and it follows that one half life is 3.5 yrs.
True because hydrogen ions combines with h2o to make hydronium ion, so in a sense h2o is acting like a base.
