Answer:
hmm let's see
Explanation:
ok, ill use the second equation of motion, u see its quite simple
recall that
average velocity= u+v/2
now think of that v like a box you can can call it velocity lol obviously its velocity
now remember the first equation of motion which is
v=u+at now this is inside the box, now you have to replace the v with it
then it becomes u+u+at/2
now u notice there are two initial velocity u know what to do with that
now it becomes
2u + at/2 now since the numerator applies to both then you can simplify it like this
2u/2+at/2
all the same the pont im trying to make is that you can use imaginative ways to mater derivation you can also reverse it if you don't unferstand you can drop your number
The momentum would be 9 kg
Answer:
TERMINUS ANTE QUEM
Explanation: Terminus ante quem is an Archeological an a Latin term used to describe the date before which an event or events took place,it is also used to show the date before which Archeological works have been deposited in a given area.
Example, a pottery dating to the 4th century AD found on a surface would give that pottery with a terminus ante quem of the 4thcentury AD.
This type of cross dating can either be TERMINUS ANTE QUEM OR TERMINUS POST QUEM.
Answer:
The neutron can be found in the nucleus of the atom with the proton.
Answer:
the answers the correct one is cη
Explanation:
In this simple pendulum experiment the student observes a significant change in time between each period. This occurs since an approximation used is that the sine of the angle is small, so
sin θ = θ
with this approach the equation will be surveyed
d² θ / dt² = - g / L sin θ
It is reduced to
d² θ / dt² = - g / L θ
in which the time for each oscillation is constant, for this approximation the angle must be less than 10º so that the difference between the sine and the angles is less than 1%
The angle is related to the height of the pendulum
sin θ = h / L
h = L sin θ.
Therefore the student must be careful that the height is small.
When reviewing the answers the correct one is cη
