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Mashcka [7]
3 years ago
12

How to remember physics derivation easier? ​

Physics
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

hmm let's see

Explanation:

ok, ill use the second equation of motion, u see its quite simple

recall that

average velocity= u+v/2

now think of that v like a box you can can call it velocity lol obviously its velocity

now remember the first equation of motion which is

v=u+at now this is inside the box, now you have to replace the v with it

then it becomes u+u+at/2

now u notice there are two initial velocity u know what to do with that

now it becomes

2u + at/2 now since the numerator applies to both then you can simplify it like this

2u/2+at/2

all the same the pont im trying to make is that you can use imaginative ways to mater derivation you can also reverse it if you don't unferstand you can drop your number

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When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 43.
zmey [24]

To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,

\tau = r F

Here,

r = Radius

F = Force

Now the units,

r = 1.95cm = 1.95*10^{-2}m

Replacing,

\tau = (1.95*10^{-2})(43.5N)

\tau = 0.8483N\cdot m

Therefore the torque that the muscle produces on the wrist is 0.85N\cdot m

3 0
4 years ago
a 2,400 kg car drives north towad a 60kg shopping cartthat has a velocity of zero the two objects collide giving the car a final
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Answer:

4.552m/s

Explanation:

V=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{1} } =\frac{2400*4.33+60*8.88}{2400}=4.552m/s

7 0
3 years ago
Diagram of an atom with labels
lina2011 [118]

See this. I hope you find your answer

6 0
3 years ago
A negative charge of -6.0x10-6 C exerts an
Ray Of Light [21]

The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C

<h3>Coulomb's law equation </h3>

F = Kq₁q₂ / r²

Where

  • F is the force of attraction
  • K is the electrical constant
  • q₁ and q₂ are two point charges
  • r is the distance apart

<h3>How to determine the second charge </h3>
  • Charge 1 (q₁) = –6×10¯⁶ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 0.05 m
  • Force (F) = 65 N
  • Charge 2 (q₂) =?

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Divide both side by Kq₁

q₂ = Fr² / Kq₁

q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)

q₂ = +3.0×10¯⁶ C (since the force is attractive)

Learn more about Coulomb's law:

brainly.com/question/506926

7 0
2 years ago
Which statement about thin lenses is correct? In each case, we are considering only a single lens. A. A diverging lens always pr
Alexus [3.1K]

Answer:

E) true. The image is always virtual and erect

Explanation:

In this exercise we are asked to find the correct statements,

for this we can use the constructor equation

     1 / f = 1 / p + 1 / q

where f is the focal length, p the distance to the object and q the distance to the image

In diverging lenses, the focal length is negative and the image is virtual and erect

In convergent lenses, the positive focal length, if the object is farther than the focal length, the image is real and inverted, and if the object is at a shorter distance than the focal length, the image is virtual and straight.

With this analysis let's review each statement

A) False. The image is right

B) False. The type of image depends on where the object is with respect to the focal length

C) False. The real image is always inverted

D) False. The image is always virtual

E) true. The image is always virtual and erect

6 0
3 years ago
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