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3 years ago

The neutron is located in the what part of the atom?

Physics

2 answers:

Studentka2010 [4]3 years ago

8 0

Answer:

The neutron is located in the nucleus of an atom

Explanation:

Atom contain proton , neutron and electron. The electron is found in the outer part of an atom. The electron revolves around the atom. It determines how atom of elements are bonded.

The neutron and proton determines the mass of an atom. The proton number plus the neutron number determines the mass number of an element. The proton and neutron are located in the nucleus of an atom. The proton is usually positively charged while the neutron is neutral.

The neutron is located in the nucleus of an atom and it is neutral. The picture below demonstrates the location of neutron in an atom

kolbaska11 [484]3 years ago

4 0

Answer:

The neutron can be found in the nucleus of the atom with the proton.

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Questions

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Precisely, water has to absorb 4,184 Joules of heat (1 calorie) for the temperature of one kilogram of water to increase 1°C. For comparison sake, it only takes 385 Joules of heat to raise 1 kilogram of copper 1°C.

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3 years ago

Suppose that two objects attract each other with a gravitational force of 50N. If the mass

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Answer:

112.5 N

Explanation:

50 = GMm/r^2

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3 years ago

A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.6 m/s . Two seconds later t

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Answer:

A) t = 7.0 s

B) x = 25 m

C) v = 10 m/s

Explanation:

The equations for the position and velocity of an object traveling in a straight line is given by the following expressions:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

A)When both friends meet, their position is the same:

x bicyclist = x friend

x0 + v0 · t + 1/2 · a · t² = x0 + v · t

If we place the center of the frame of reference at the point when the bicyclist starts following his friend, the initial position of the bicyclist will be 0, and the initial position of the friend will be his position after 2 s:

Position of the friend after 2 s:

x = v · t

x = 3.6 m/s · 2 s = 7.2 m

Then:

1/2 · a · t² = x0 + v · t v0 of the bicyclist is 0 because he starts from rest.

1/2 · 2.0 m/s² · t² = 7.2 m + 3.6 m/s · t

1 m/s² · t² - 3.6 m/s · t - 7.2 m = 0

Solving the quadratic equation:

t = 5.0 s

It takes the bicyclist (5.0 s + 2.0 s) 7.0 s to catch his friend after he passes him.

B) Using the equation for the position, we can calculate the traveled distance. We can use the equation for the position of the friend, who traveled over 7.0 s.

x = v · t

x = 3.6 m/s · 7.0 s = 25 m

(we would have obtained the same result if we would have used the equation for the position of the bicyclist)

C) Using the equation of velocity:

v = a · t

v = 2.0 m/s² · 5.0 s = 10 m/s

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4 years ago

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