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Andreas93 [3]
3 years ago
8

Which pair of elements will form a covalent bond?

Chemistry
2 answers:
Dominik [7]3 years ago
7 0

Answer: Option (A) is the correct answer.

Explanation:

A covalent bond is formed when there occurs sharing of electrons between atoms.

For example, in hydrogen atom there is one electron in its orbit and in a chlorine atom there is 7 valence electron. So, in order to attain stability both hydrogen and chlorine share electrons when they come close to each other.

Whereas except hydrogen and chlorine rest of the given atoms will form ionic bond, that is, bond formed by transfer of electrons.

Thus, we can conclude that a pair of hydrogen and chlorine will form a covalent bond.

I am Lyosha [343]3 years ago
5 0

\boxed{{\text{A}}{\text{. hydrogen and chlorine}}} will form a covalent bond.

Further Explanation:

The bond that is formed by the mutual sharing of electrons between the bonded atoms is called a covalent bond. It is also known as a molecular bond. Covalent compounds are those compounds which are formed by the electron sharing between two or more non-metals.

Following are some of the properties of covalent compounds:  

1. These are brittle solids.

2. Low melting and boiling points.

3. Poor conductors of heat and electricity.

4. Low enthalpy of fusion.

Boron trichloride \left( {{\text{BC}}{{\text{l}}_3}} \right), silicon dioxide   \left( {{\text{Si}}{{\text{O}}_2}} \right), and xenon hexafluoride  \left( {{\text{Xe}}{{\text{F}}_{\text{6}}}} \right) are some examples of covalent compounds.

Ionic bond results from the interaction of a metal with a non-metal. Metal atom loses electron by virtue of its low ionization energy and forms a cation. This electron is gained by the non-metal atom and an anion is formed.

Following are some of the properties of ionic compounds:  

1. These are hard solids.

2. High melting and boiling points.

3. Good conductors of heat and electricity.

4. High enthalpy of fusion.

Sodium chloride (NaCl), potassium chloride (KCl) and barium oxide (BaO) are some of the examples of ionic compounds.

(A) Both hydrogen and chlorine are non-metals and the bond formed between two non-metals is a covalent bond. So hydrogen and chlorine will form covalent bonds with each other and the resulting compound HCl will be covalent compound.

(B) Sodium is metal while chlorine is a non-metal. So ionic bond will be formed by their interaction and the compound NaCl will be an ionic compound.

(C) Copper is metal while bromine is a non-metal. So ionic bond will be formed by their interaction and the compound CuBr will be an ionic compound.

(D)  Zinc is metal while bromine is a non-metal. So ionic bond will be formed by their interaction and the compound ZnBr will be an ionic compound.

So covalent bond will only be formed by hydrogen and chlorine.

Learn more:

1. Identification of ionic bonding: brainly.com/question/1603987

2. The main purpose of conducting experiments: brainly.com/question/5096428

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ionic and covalent compounds

Keywords: covalent compounds. chlorine, hydrogen, sodium, copper, zinc, metal, non-metal, cation, anion, mutual sharing, molecular bond, hard, brittle, enthalpy of fusion, heat, electricity, conductors, boiling points.

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ycow [4]
The formula of alcohol are
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we have 0.043:0.130.;0.022 as C:H:O. Diving by the smallest no. 0.022 we get 1.95:5.9:1 or 2:6:1 as C:H:O.

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3 years ago
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Nuclear decay<br>27Al + He 》 39P<br>​
dybincka [34]

Answer:

_{13}^{27}\text{Al} + \rm _{2}^{4}\text{He} \longrightarrow \, _{15}^{31}\text{P}

Explanation:

The unbalanced nuclear equation is

^{27}\text{Al} + \rm \text{He} \longrightarrow \, ^{31}\text{P}

We can insert the subscripts, because these are the atomic numbers of the elements

_{13}^{27}\text{Al} + \, \rm _{2}\text{He} \longrightarrow \, _{15}^{31}\text{P}

That leaves only the superscript of He to be determined,

The main point to remember in balancing nuclear equations is that the sums of the superscripts must be the same on each side of the equation.  

Then

27 + x = 31, so x = 31 - 27 = 4

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_{13}^{27}\text{Al} + \, \rm _{2}^{4}\text{He} \longrightarrow \, _{15}^{31}\text{P}

6 0
3 years ago
1. If a solution of sodium chloride has 22.3 g of
lina2011 [118]

<u>We are given:</u>

Mass of NaCl in the given solution = 22.3 grams

Volume of the given solution = 2 L

<u></u>

<u>Number of Moles of NaCl:</u>

We know that the number of moles = Given mass / Molar mass

Number of moles = 22.3 / 58.44 = 0.382 moles

<u></u>

<u>Molarity of NaCl in the Given solution:</u>

We know that Molarity of a solution = Moles of Solute / Volume of Solution(in L)

Molarity = 0.382 / 2

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3 years ago
Lance is a 60-kg runner who, on a good day, runs at a speed of 5 m/s. What is his kinetic energy when he runs at this speed? *
Contact [7]

Answer:

His kinetic energy when he runs at that 5 m/s is 750 joules

Explanation:

The given information are;

The mass of, Lance, the runner = 60-kg

The speed by which Lance is running = 5 m/s

The kinetic energy, KE, is given by the relation;

KE = 1/2×m×v²

Where;

m = The mass = 60-kg

v = The instantaneous speed of motion = 5 m/s

The kinetic energy can be found by substituting the values of the variables in the kinetic energy equation as follows;

KE = 1/2 × 60 kg × (5 m/s)² = 750 joules

His kinetic energy when he runs at that 5 m/s is 750 joules.

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storchak [24]

Answer:

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Explanation:

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We need to know, where do the ions come from. In this case, K⁺ comes from the KOH which is a strong base and Cl⁻ comes from the HCl, a strong acid. In conclussion, both are the conjugate weak acid and base, respectively. They do not make hydrolysis, so this salt is neutral. No protons or hydroxides are given.

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ClO⁻  +  H₂O  ⇄  HClO  +  OH⁻

We are giving hydroxides to medium, so the salt is basic.

3 0
4 years ago
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