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Andreas93 [3]
3 years ago
8

Which pair of elements will form a covalent bond?

Chemistry
2 answers:
Dominik [7]3 years ago
7 0

Answer: Option (A) is the correct answer.

Explanation:

A covalent bond is formed when there occurs sharing of electrons between atoms.

For example, in hydrogen atom there is one electron in its orbit and in a chlorine atom there is 7 valence electron. So, in order to attain stability both hydrogen and chlorine share electrons when they come close to each other.

Whereas except hydrogen and chlorine rest of the given atoms will form ionic bond, that is, bond formed by transfer of electrons.

Thus, we can conclude that a pair of hydrogen and chlorine will form a covalent bond.

I am Lyosha [343]3 years ago
5 0

\boxed{{\text{A}}{\text{. hydrogen and chlorine}}} will form a covalent bond.

Further Explanation:

The bond that is formed by the mutual sharing of electrons between the bonded atoms is called a covalent bond. It is also known as a molecular bond. Covalent compounds are those compounds which are formed by the electron sharing between two or more non-metals.

Following are some of the properties of covalent compounds:  

1. These are brittle solids.

2. Low melting and boiling points.

3. Poor conductors of heat and electricity.

4. Low enthalpy of fusion.

Boron trichloride \left( {{\text{BC}}{{\text{l}}_3}} \right), silicon dioxide   \left( {{\text{Si}}{{\text{O}}_2}} \right), and xenon hexafluoride  \left( {{\text{Xe}}{{\text{F}}_{\text{6}}}} \right) are some examples of covalent compounds.

Ionic bond results from the interaction of a metal with a non-metal. Metal atom loses electron by virtue of its low ionization energy and forms a cation. This electron is gained by the non-metal atom and an anion is formed.

Following are some of the properties of ionic compounds:  

1. These are hard solids.

2. High melting and boiling points.

3. Good conductors of heat and electricity.

4. High enthalpy of fusion.

Sodium chloride (NaCl), potassium chloride (KCl) and barium oxide (BaO) are some of the examples of ionic compounds.

(A) Both hydrogen and chlorine are non-metals and the bond formed between two non-metals is a covalent bond. So hydrogen and chlorine will form covalent bonds with each other and the resulting compound HCl will be covalent compound.

(B) Sodium is metal while chlorine is a non-metal. So ionic bond will be formed by their interaction and the compound NaCl will be an ionic compound.

(C) Copper is metal while bromine is a non-metal. So ionic bond will be formed by their interaction and the compound CuBr will be an ionic compound.

(D)  Zinc is metal while bromine is a non-metal. So ionic bond will be formed by their interaction and the compound ZnBr will be an ionic compound.

So covalent bond will only be formed by hydrogen and chlorine.

Learn more:

1. Identification of ionic bonding: brainly.com/question/1603987

2. The main purpose of conducting experiments: brainly.com/question/5096428

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ionic and covalent compounds

Keywords: covalent compounds. chlorine, hydrogen, sodium, copper, zinc, metal, non-metal, cation, anion, mutual sharing, molecular bond, hard, brittle, enthalpy of fusion, heat, electricity, conductors, boiling points.

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ycow [4]

No of moles:-

\\ \tt\longmapsto \dfrac{No\:of\:atoms}{Avagadro's\; number}

\\ \tt\longmapsto \dfrac{7.62(10^{25})}{6.022(10^{23})}

\\ \tt\longmapsto 126.5mol

8 0
2 years ago
Please help me the picture is above.
Andreas93 [3]

Answer:

A

Explanation:

bc inorganic compoud refers to all compound that do not contain carbons.

4 0
2 years ago
A student was assigned the task of determining the identity of an unknown liquid. The student weighed a clean, dry 250-mL Erlenm
LiRa [457]

Answer:

248.4 mL

Explanation:

Erlenmeyer = 78.649 g

Erlenmeyer + Water = 327.039 g

Water = (Erlenmeyer + Water) - Erlenmeyer

Water = 327.039 - 78.649

Water = 248.4 g

if the density of water is 1 g/mL, we can say that each mL of water weigh 1 g, so we have 248.4 mL of water in the Erlenmeyer Flask.

4 0
3 years ago
If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of NaCl would be made?
Ket [755]
Number of moles of FeCl2 used = mass/ molar mass 
Number of moles = 507/126.751 = 4.
If one mole of Fe reacts with two moles of sodium 
Then 4 moles of Fe produces 8 moles of sodium.
Number of moles of sodium = mass/molar mass
Molar mass of sodium chloride = 23 +35.5 = 58.5 g/mol
Hence mass = 8 * 58.5 = 468 g. Hence Option A.

6 0
2 years ago
What is the pOH of a 0.150 M solution of potassium nitrite? (Ka HNO2 = 4.5 x 10−4 )
yanalaym [24]

Answer:

11.9 is the pOH of a 0.150 M solution of potassium nitrite.

Explanation:

Solution :  Given,

Concentration (c) = 0.150 M

Acid dissociation constant = k_a=4.5\times 10^{-4}

The equilibrium reaction for dissociation of HNO_2 (weak acid) is,

                           HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+

initially conc.         c                       0         0

At eqm.              c(1-\alpha)                c\alpha        c\alpha

First we have to calculate the concentration of value of dissociation constant (\alpha ).

Formula used :

k_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}

Now put all the given values in this formula ,we get the value of dissociation constant (\alpha ).

4.5\times 10^{-4}=\frac{(0.150\alpha)(0.150\alpha)}{0.150(1-\alpha)}

4.5\times 10^{-4} - 4.5\times 10^{-4}\alpha =0.150\alpha ^2

0.150\alpha ^2+4.5\times 10^{-4}\alpha-4.5\times 10^{-4}=0

By solving the terms, we get

\alpha=0.0533

No we have to calculate the concentration of hydronium ion or hydrogen ion.

[H^+]=c\alpha=0.150\times 0.0533=0.007995 M

Now we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.007995 M)

pH=2.097\approx 2.1

pH + pOH = 14

pOH =14 -2.1 = 11.9

Therefore, the pOH of the solution is 11.9

4 0
3 years ago
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