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2 years ago

Can someone help me with thins, im to lazy to read rn i did freaking 47 over due homeworkkkk

Chemistry

1 answer:

AysviL [449]2 years ago

3 0

Smh das tough and all and same i got hella overdue

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The whiye pigment TiO2 is prepared by the reaction of titanium tetrachloride, TiCl4, with water vapor in the gas phase:

omeli [17]

Answer:

$\boxed{\text{62.1 kJ}}$

Explanation:

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

$\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})$

TiCl₄(g) + 2H₂O(g) ⟶ TiO₂(s) + 4HCl(g)

ΔH°f/kJ·mol⁻¹: -763.2 -241.828 -939.7 -92.307

$\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [-939.7 + 4(-92.307)] - [-763.2 + 2(-241.828)\\& = & [-939.7 - 369.228] - [-763.2 - 483.656]\\& = & -1308.928 + 1246.856\\& = & \mathbf{-62.1}\\\end{array}\\\text{The amount of heat evolved is } \boxed{\textbf{62.1 kJ}}$

5 0

3 years ago

A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of thi

Naddika [18.5K]

Imagine we have mass of solvent 1kg (1000g)
According to that: $molality =n(solute) / m(solvent) =\ \textgreater \ 4.8m = 4.8mole / 1kg$
= 4.8 mole * 98 g/mole = 470g
$m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \$ $=\ \textgreater \ Molarity = 4.8 mole / 1.2 L = 4 M$ m(H2SO4) which is =470g

m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =>
$Molarity = n(solute) / V(solution) =\ \textgreater \$

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2 years ago

Given the balanced equation, calculate the mass of product that can be prepared from 2.10 g of zinc metal. 2Zn(s)+O2(g)→2ZnO(s)

vazorg [7]

Botox & Glade Juice w/ Apple Cider Vinegar

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3 years ago

What is the SI unit for energy? How is it abbreviated?

hjlf

Answer:

Joule - J

Explanation:

As energy is defined via work, the SI unit of energy is the same as the unit of work – the joule (J).

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2 years ago

HELP DUE MONDAY!! Don’t understand

Katyanochek1 [597]

Answer:

Concept: Chemical Analysis

You need to start by graphing the data and then analyzing it.
We can see that the horse has a distance in meters of 980 at the end of the 10 seconds hence it is the fastest.
The horse line has a linearly representation, while the alternate line has parabolic tendencies towards the end. The steeper line indicates a faster change in time or velocity which results in a greater distance traveled indicating that the horse is faster.
*I have confidence you can graph that*

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2 years ago