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puteri [66]
4 years ago
13

a pumpkin with a mass of 2.5 kg was pushed toward a wall the average acceleration of the pumpkin was 10.7 miles per second squar

ed how much force was applied to the pumpkin to make it move

Physics
2 answers:
taurus [48]4 years ago
7 0

The answer would be 26.75 I am on K12 and took the test. Hope this helps :)


Sati [7]4 years ago
6 0
Alright, to begin with. The unit of Force is in Newtons. Meaning the first two options are out of the answers. Now in order to find the force. You will need to take the mass and multiply that by the acceleration. Which will give you 26.75 Newtons.
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"A hiker starts at point P and walks 2.0 kilometers due east and then 1.4 kilometers due north. The vectors in the diagram below
Law Incorporation [45]
Here, you need to use your "Protractor" as it is given in the question, but we can calculate the value with the help of our mathematical calculation too:
[ Protractor can be use only in real life, not here ]

Draw an imaginary line from initial position to final position.
Now, In that triangle, tan x = P/B
tan x = 1.4 / 2
tan x = 0.70
x = tan⁻¹ (0.70)
x = 35  [ tan 35 = 0.70 ]

In short, Your Answer would be 35 degrees

Hope this helps!
3 0
3 years ago
Which statement is correct? (2 points)
Lemur [1.5K]

Answer:

When a neutral atom looses an electron to another neutral atom, two charged atoms are created.

Explanation:

On the off chance that one of the two unbiased particle looses an electron, it turns out to be emphatically (charge: +1), in light of the fact that the electron conveys a charge of - 1. Thus, the other atom which acknowledges the electron turns out to be adversely charged (charge: - 1). And in the end, we will have two charged atoms.

7 0
3 years ago
While rearranging a dorm room, a student does 310 J of work in moving a desk 2.9 m. What was the magnitude of the applied horizo
Viefleur [7K]

Answer:

The horizontal force is 106.89 N.

Explanation:

Given that,

Work done = 310 J

Distance = 2.9 m

We need to calculate the horizontal force

Using formula of work done

W= Fd\cos\theta

Where, \theta=0^{\circ}

W=F\cdot d

Put the value into the formula

310=F\cdot 2.9

F=\dfrac{310}{2.9}

F=106.89\ N

Hence, The horizontal force is 106.89 N.

3 0
3 years ago
What is the purpose of life?
postnew [5]

Answer:

to live honorable

Explanation:

4 0
3 years ago
A loaded 320 kg toboggan is traveling on smooth horizontal snow at 4.60 m/s when it suddenly comes to a rough region. The region
MariettaO [177]

Answer:

367.04 N

Explanation:

Frictional force = mass of the toboggan×deceleration caused by the rough region

Fr = m×ar....................... Equation 1

Where Fr = Average frictional force, m = mass of loaded toboggan, ar = deceleration cause by the rough region.

We can calculate for ar using the formula below

v² = u²+2ars................... Equation 2

make ar the subject of the equation

ar = (v²-u²)/2s.................. Equation 3

Where v = final velocity of the toboggan, u = initial velocity of the toboggan, s = distance or length of the rough region

Given: v = 1.2 m/s, u = 4.6 m/s, s = 8.6 m

Substitute into equation 3

ar = (1.2²-4.6²)/(2×8.6)

ar = (1.44-21.16)/17.2

ar = -19.72/17.2

ar = -1.147 m/s²

Also given: m = 320 kg

Substitute into equation 1

Fr = 320(-1.147)

Fr = -367.04 N

Note: The negative sign tells that the frictional force opposes the motion of the toboggan

6 0
3 years ago
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