Answer:
Explanation:
Height reached = 164m
If velocity of launch be u
u² = 2gh
= 2 x 9.8 x 164
= 3214.4
u = 56.7 m /s
difference in u = 1/2 (diff in h / h) x u
1/2 x 1/164 x 56.7
.17 or .2
u = 56.7 ± .2 m /s
or 57± 1
b ) During the displacement of .300 m , there is acceleration to achieve velocity of 56.7 m /s
v² = 2as
a = v² / 2s
= 56.7² / (2 x .3)
= 5358.15 m /s²
diff in a
= 1/2 x (.02 / .3) x 5358.15
178.6
a = 5358.1 ±178.6
c ) force on the ground
mass ( g + a )
= 100 x ( 9.8 +5358.1)
= 536790 N
error in force = (.1/100 + 178.6 / 5358 ) x 536790
=( .01 +.03)x 536790
= 21471
(536790 ± 21471) N
Answer:
they are all living things in an ecosystem
Explanation:
Hope this helps - Good luck ^w
Answer:
★ In a hypotonic solution, the solute concentration is lower than inside the cell. If the water continues to move into the cell, it can stretch the cell membrane to the point the cell bursts (lyses) and dies.
Explanation:
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